C1
If sinx = 3/5 and x is acute, calculate cosx and tanx
not really sure what im supposed to be doing, can somebody explain?
not really sure what im supposed to be doing, can somebody explain?
Original post by jacksonmeg
If sinx = 3/5 and x is acute, calculate cosx and tanx
not really sure what im supposed to be doing, can somebody explain?
not really sure what im supposed to be doing, can somebody explain?
Draw a right angled triangle
Label an angle as x
Label the 2 sides you know are 3 and 5
Find the other side
Write down Tan(x) and Cos(x)
Original post by TenOfThem
Draw a right angled triangle
Label an angle as x
Label the 2 sides you know are 3 and 5
Find the other side
Write down Tan(x) and Cos(x)
Label an angle as x
Label the 2 sides you know are 3 and 5
Find the other side
Write down Tan(x) and Cos(x)
so cosx = 4/5
tanx = 5/4 ?
if sinx is obtuse what should I do then?
Original post by jacksonmeg
so cosx = 4/5
tanx = 5/4 ?
if sinx is obtuse what should I do then?
tanx = 5/4 ?
if sinx is obtuse what should I do then?
Then you have to consider that sin(x) would be +ve but that cos(x) and tan(x) would be -ve
ve?
Original post by jacksonmeg
ve?
-ve = negative
Original post by joostan
-ve = negative
negative angles? what? :P
Original post by jacksonmeg
ve?
Positive and negative
Original post by jacksonmeg
negative angles? what? :P
Sorry?
Not sure what you are asking
Firstly, you can have negative angles
Secondly, no - I said that Cosx and Tanx would be negative
Original post by TenOfThem
Sorry?
Not sure what you are asking
Firstly, you can have negative angles
Secondly, no - I said that Cosx and Tanx would be negative
Not sure what you are asking
Firstly, you can have negative angles
Secondly, no - I said that Cosx and Tanx would be negative
how would i find the values?
Original post by jacksonmeg
how would i find the values?
The actual numbers do not change
Original post by TenOfThem
The actual numbers do not change
I still dont understand how to do it, how do you get a negative number when all the sides are positive?
Original post by jacksonmeg
I still dont understand how to do it, how do you get a negative number when all the sides are positive?
You asked about an obtuse angle
Have you done any work this year on obtuse angles, using the trig graphs or the CAST diagram
Or can you recall this work from GCSE
(edited 10 years ago)
Original post by TenOfThem
You asked about an obtuse angle
Have you done any work this year on obtuse angles, using the trig graphs or the CAST diagram
Or can you recall this work from GCSE
Have you done any work this year on obtuse angles, using the trig graphs or the CAST diagram
Or can you recall this work from GCSE
no we havent
Original post by jacksonmeg
no we havent
Then you will probably deal with obtuse, reflex, and negative angles next
Original post by TenOfThem
Then you will probably deal with obtuse, reflex, and negative angles next
can u explain it?
Original post by jacksonmeg
can u explain it?
I can
And to do so well I would usually take a double lesson
So, wait until you cover this in class
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