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ANSWERS: OCR Physics B(Advancing Physics) G491~ 20th May 2014~ AS Physics

Mutleybm1996

OCR PHYSICS B(ADVANCING PHYSICS)~ Physics in Action!

ANSWERS ARE ON POST 559

Welcome to the OCR Physics B (G491) Exam Thread!

Feel free to share notes/tips/materials/questions and thoughts on the exam.

DATE OF EXAM: G491 - 1Hr - 20TH MAY 2014 - AM

SYLLABUS:

http://www.ocr.org.uk/Images/74952-specification.pdf

- Scroll down to G491 ( PAGES 16-20)

http://www.ocr.org.uk/qualifications/as-a-level-gce-physics-b-advancing-physics-h159-h559/

( Legacy OCR papers)

USEFUL REVISION WEBSITES:

http://matthew-arnold.tmp.synergy-learning.com/course/view.php?id=62

http://en.wikibooks.org/wiki/A-level_Physics_(Advancing_Physics)

http://www.johnbright.conwy.sch.uk/depts/science/Content/Revision_Notes/Y12/Physics/G491%20-%20Physics%20in%20Action%20-%20Revision.pdf

ADVICE:

I personally would start revision now, even if its 30 minutes a day it will just reduce you with the amount of workload and revision you will have to do as the exam gets closer especially if you are resiting any exams!

If you want any help just post a question here and I or someone else will help!

Finally Good luck to all of you!

(edited 9 years ago)

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Reply 2

Mutleybm1996

OP

19

So i'm the only one sitting this exam?

Posted from TSR Mobile

Reply 3

ZahraP

Hey

You're not the the only one :smile:

How are you finding the electricity section i think its the part where i'm gna struggle in the exam :s-smilie:

Reply 4

HappyCheesecake

8

Oooh, I'm sitting this exam too. :redface:

How are you finding revision?

Reply 5

Mutleybm1996

OP

19

Original post by HappyCheesecake

Oooh, I'm sitting this exam too. :redface:

How are you finding revision?

Easier than G492!

Posted from TSR Mobile

Reply 6

H0PEL3SS

12

Original post by Mutleybm1996

Easier than G492!

Posted from TSR Mobile

Bits and pieces of it, definitely. But, as I'm also taking M1, G492 isn't as difficult.

Reply 7

HappyCheesecake

8

Original post by Mutleybm1996

Easier than G492!

Posted from TSR Mobile

I haven't started G491 yet :colondollar:

but I've had a look at G492. Doing M1 helps with that.

What do you think of the Advanced notice paper?

Reply 8

Kuna9613

1

Help please! I'm stuck on question 5 of this paper:
http://www.ocr.org.uk/Images/61672-question-paper-unit-g491-physics-in-action.pdf

The mark scheme answer is (at least 12 x 103 x 11 ) =1.3(2) x 105 (bit s-1) - But i don't know where to get the 103 from!

Many thanks

Reply 9

ZahraP

Original post by Kuna9613

Help please! I'm stuck on question 5 of this paper:
http://www.ocr.org.uk/Images/61672-question-paper-unit-g491-physics-in-action.pdf

The mark scheme answer is (at least 12 x 103 x 11 ) =1.3(2) x 105 (bit s-1) - But i don't know where to get the 103 from!

Many thanks

Rate of transmission of a digital signal (bits per second)= sample per second x bits per sample

Therefore it should be 12x10^3x11 which equals 132000, this is accepted by the mark scheme.

I have no idea where the have got 103 from though :s-smilie:

Reply 10

AnthonyThomas

Original post by ZahraP

Hey

You're not the the only one :smile:

How are you finding the electricity section i think its the part where i'm gna struggle in the exam :s-smilie:

Yep, thats the section im going to struggle in too. Its the most difficult. :confused:

Reply 11

stupendousp

http://www.ocr.org.uk/Images/144795-question-paper-unit-g491-01-physics-in-action.pdf

can someone please explain how to do 10. c) i), the mark scheme is useless

Reply 12

Knowing

1

Original post by Kuna9613

Help please! I'm stuck on question 5 of this paper:
http://www.ocr.org.uk/Images/61672-question-paper-unit-g491-physics-in-action.pdf

The mark scheme answer is (at least 12 x 103 x 11 ) =1.3(2) x 105 (bit s-1) - But i don't know where to get the 103 from!

Many thanks

Original post by ZahraP

Rate of transmission of a digital signal (bits per second)= sample per second x bits per sample

Therefore it should be 12x10^3x11 which equals 132000, this is accepted by the mark scheme.

I have no idea where the have got 103 from though :s-smilie:

I think the markscheme means 10^3 (10 cubed = 1000) - because the sampling rate is 12kHz (12,000 Hz) - so thats where the "103" or "10^3" came from :smile:

Reply 13

Kuna9613

1

Original post by Knowing

I think the markscheme means 10^3 (10 cubed = 1000) - because the sampling rate is 12kHz (12,000 Hz) - so thats where the "103" or "10^3" came from :smile:

That makes perfect sense; thank you

Reply 14

kobobo

1

The grade boundaries are becoming ridiculous. In Jan 2010 the grade boundaries for an A was 36 and now it is like 45 for an A! I don't think the exams have got any easier through out the years so why have they increased the grade boundaries!?

Reply 15

kobobo

1

Does anyone know how to do question 8c from the May 2011 paper? I don't understand what it says on the mark scheme or how to work it out.

Reply 16

Knowing

1

Original post by kobobo

Does anyone know how to do question 8c from the May 2011 paper? I don't understand what it says on the mark scheme or how to work it out.

Since both shuttles are said to be identical, you can work out the ratio of how far they are away from the camera by measuring the size of the shuttle images.

Size of Atlantis Image = 2.6cm
Size of Endeavour Image = 0.7cm

Since both shuttles are identical, we can say that the real object size for both = 1.

The equation you need is Image size = Object size/Distance from camera.
^ Rearrange the equation, and input the values, and you get this:

Distance of Atlantis from Camera = 1/2.6
Distance of Endeavor from Camera = 1/0.7

Now put these figures into the ratio equation they give you in the question:

(1/0.7) / (1/2.6)

This will give you ~3.7(14...etc.), which is the right answer

Hope this makes sense

Reply 17

kobobo

1

Original post by Knowing

Since both shuttles are said to be identical, you can work out the ratio of how far they are away from the camera by measuring the size of the shuttle images.

Size of Atlantis Image = 2.6cm
Size of Endeavour Image = 0.7cm

Since both shuttles are identical, we can say that the real object size for both = 1.

The equation you need is Image size = Object size/Distance from camera.
^ Rearrange the equation, and input the values, and you get this:

Distance of Atlantis from Camera = 1/2.6
Distance of Endeavor from Camera = 1/0.7

Now put these figures into the ratio equation they give you in the question:

(1/0.7) / (1/2.6)

This will give you ~3.7(14...etc.), which is the right answer

Hope this makes sense

Thank You so much!!!!!!!! I forgot to read that the space shuttles are identical, so once i measured the shuttles i was a bit confused what to do next. As the question says ratio would 3.71 be the answer?

Reply 18

Robbo54

2

Out of all my exams, this is the exam I am most worried for. The contextual nature of G491 makes picking information out of the exam quite difficult.

In regards to past papers, I've been getting ~45-54.

Reply 19

Mutleybm1996

OP

19

Original post by ZahraP

Hey

You're not the the only one :smile:

How are you finding the electricity section i think its the part where i'm gna struggle in the exam :s-smilie:

Original post by HappyCheesecake

Oooh, I'm sitting this exam too. :redface:

How are you finding revision?

Original post by H0PEL3SS

Bits and pieces of it, definitely. But, as I'm also taking M1, G492 isn't as difficult.

Original post by Kuna9613

Help please! I'm stuck on question 5 of this paper:
http://www.ocr.org.uk/Images/61672-question-paper-unit-g491-physics-in-action.pdf

The mark scheme answer is (at least 12 x 103 x 11 ) =1.3(2) x 105 (bit s-1) - But i don't know where to get the 103 from!

Many thanks

Original post by ZahraP

Rate of transmission of a digital signal (bits per second)= sample per second x bits per sample

Therefore it should be 12x10^3x11 which equals 132000, this is accepted by the mark scheme.

I have no idea where the have got 103 from though :s-smilie:

Original post by stupendousp

http://www.ocr.org.uk/Images/144795-question-paper-unit-g491-01-physics-in-action.pdf

can someone please explain how to do 10. c) i), the mark scheme is useless

Original post by Knowing

I think the markscheme means 10^3 (10 cubed = 1000) - because the sampling rate is 12kHz (12,000 Hz) - so thats where the "103" or "10^3" came from :smile:

Are you folks still at school? Could you ask your teachers if we need to know how to apply image processing techniques such as smoothing,edge detection and noise removal using the formulae in the book? I emailed my teacher but she's not in school until after the exam apparently and i can't find it in the specification(which we all know is rubbish)

ANSWERS: OCR Physics B(Advancing Physics) G491~ 20th May 2014~ AS Physics

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