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C3 maximum of graph question
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BananaBanana101
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#1
Can someone please explain to me why the answer to (b) (I) is 4/12-10
I feel like I don't fully understand how to calculate the maximum and minimum of a graph
Thank you
I feel like I don't fully understand how to calculate the maximum and minimum of a graph
Thank you
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BananaBanana101
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#2
(Original post by BananaBanana101)
Can someone please explain to me why the answer to (b) (I) is 4/12-10
I feel like I don't fully understand how to calculate the maximum and minimum of a graph
Thank you
Can someone please explain to me why the answer to (b) (I) is 4/12-10
I feel like I don't fully understand how to calculate the maximum and minimum of a graph
Thank you
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Covington4
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#3
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#3
(Original post by BananaBanana101)
Can someone please explain to me why the answer to (b) (I) is 4/12-10
I feel like I don't fully understand how to calculate the maximum and minimum of a graph
Thank you
Can someone please explain to me why the answer to (b) (I) is 4/12-10
I feel like I don't fully understand how to calculate the maximum and minimum of a graph
Thank you
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BananaBanana101
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#4
(Original post by Ben4)
Pretty sure you have to use your answer to part a, what did you get for that part?
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Pretty sure you have to use your answer to part a, what did you get for that part?
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10cos(theta - 0.927)
(Correct)
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testing1234568
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#5
(Original post by BananaBanana101)
10cos(theta - 0.927)
10cos(theta - 0.927)
P(theta) = 4/(12-10cos(theta-0.927))
Since this is always positive, you know that P is a maximum when the denominator ( 12 - 10cos(theta-0.927) ) on the right is as small as possible.
Can you think what the smallest value of 12 - 10cos(theta-0.927) is and when it occurs?
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BananaBanana101
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#6
(Original post by studentro)
So you can write:
P(theta) = 4/(12-10cos(theta-0.927))
Since this is always positive, you know that P is a maximum when the denominator ( 12 - 10cos(theta-0.927) ) on the right is as small as possible.
Can you think what the smallest value of 12 - 10cos(theta-0.927) is and when it occurs?
So you can write:
P(theta) = 4/(12-10cos(theta-0.927))
Since this is always positive, you know that P is a maximum when the denominator ( 12 - 10cos(theta-0.927) ) on the right is as small as possible.
Can you think what the smallest value of 12 - 10cos(theta-0.927) is and when it occurs?
Out of curiosity why am I allowed to do -10cos(theta - 0.927)
Thank you!
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testing1234568
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#7
(Original post by BananaBanana101)
So inverse cos -1 = pie add 0.927
Out of curiosity why am I allowed to do -10cos(theta - 0.927)
Thank you!
So inverse cos -1 = pie add 0.927
Out of curiosity why am I allowed to do -10cos(theta - 0.927)
Thank you!
Find the minimum value this takes and the value of theta at which it occurs.
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BananaBanana101
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#8
(Original post by studentro)
Sorry, I misread. The denominator is 12+10cos(theta-0.927).
Find the minimum value this takes and the value of theta at which it occurs.
Sorry, I misread. The denominator is 12+10cos(theta-0.927).
Find the minimum value this takes and the value of theta at which it occurs.
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testing1234568
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#9
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#9
(Original post by BananaBanana101)
No what you said is correct to the mark scheme!
No what you said is correct to the mark scheme!
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Snasher350
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#10
(Original post by BananaBanana101)
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