AQA A2 Maths 2017 - MFP3 Further Pure 3 - Wednesday 17 May [Official Thread]

Original post by OturuDansay

I couldn't do the polar to Cartesian transformation q and messed up on the hella long differential question at the end. Just made so many silly mistakes, just scraping an A

Yeah I've gotten A*s on all of them except the 2016 one where I got a 62 (B), no idea why... the questions on that paper are just weirder I guess, I made a lot of mistakes for no reason lol

Reply 45

Zxphyrs

16

Original post by OturuDansay

Did anyone struggle on 2016? Really felt short for time

Yep, fair to say i hated 2016

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Reply 46

Pierre de Fermat

Do you guys feel ready for this exam? I feel like I am ready but because it's my first exam so I'm not exactly in the 'exam mindset'. I think you just need to get a decent amount of sleep the night before

Reply 47

sadasdasdasd

do you guys know if we need to quote anything to use sin^n(x)cos(x).dx = sin^(n+1)x/(n+1) + c, or can we just get away with using it straight up

Reply 48

Pentaquark

13

Original post by sadasdasdasd

do you guys know if we need to quote anything to use sin^n(x)cos(x).dx = sin^(n+1)x/(n+1) + c, or can we just get away with using it straight up

On Jun 11 there was an integral of the form sin^2xcosx and to award method mark you can use substitution, or by inspection.
So I'm guessing yes you can go straight up without showing anything.

Reply 49

sadasdasdasd

What do you mean by inspection?

OP

Original post by sadasdasdasd

What do you mean by inspection?

Being to tell immediately that

\displaystyle \int \sin^2(x)\cos(x) .dx = \frac{1}{3}\sin^3(x)

without working out, just running through a quick substitution in your head to realise that cos(x) would cancel and ultimately you would simply need to integrate

u^2 .du

where

u=\sin(x)

Reply 51

sadasdasdasd

Original post by RDKGames

Being to tell immediately that

\displaystyle \int \sin^2(x)\cos(x) .dx = \frac{1}{3}\sin^3(x)

without working out, just running through a quick substitution in your head to realise that cos(x) would cancel and ultimately you would simply need to integrate

u^2 .du

where

u=\sin(x)

Alright cool ty

any predictions?

They tend to use a technique or something in particular in the following paper. For example they asked you to integrate (tanx)^2secx and in the following paper they ask you to integrate something very similar to that. So i would say to make sure you understand everything from the 2016 paper.

Reply 54

Eddy253

14

Original post by Chickenslayer69

Yeah I've gotten A*s on all of them except the 2016 one where I got a 62 (B), no idea why... the questions on that paper are just weirder I guess, I made a lot of mistakes for no reason lol

My god 62/75 for a B cheers AQA!

Reply 55

Original post by Eddy253

My god 62/75 for a B cheers AQA!

Yeah, it was 64 for an A I think :frown:

Main reason this paper is so hard is bc you can make one mistake and literally drop 2 grades because the boundaries are so high and close together

Reply 56

YAH_BOY_ASH

Have a question from June 2012. Given the equation r^2 = 16cosec(2theta) how would you find the minimum value of r? on the mark scheme it just says sin(2theta)=1 when minimum, don't quite understand what they mean..

Reply 57

Original post by YAH_BOY_ASH

Hi, I don't understand the markscheme for June 2014 Question 8bii)
Could someone tell me what they are doing?
;s
How is everyone feeling for the exam?

Yeah, can someone explain this please? Thanks

OP

Original post by YAH_BOY_ASH

Have a question from June 2012. Given the equation r^2 = 16cosec(2theta) how would you find the minimum value of r? on the mark scheme it just says sin(2theta)=1 when minimum, don't quite understand what they mean..

r^2

is minimised when

\csc(2\theta)

is minimised.

\csc(2\theta) \equiv \frac{1}{\sin(2\theta)}

This fraction is minimised when the denominator is as big as possible.

The maximum value the denominator can take is 1.

(edited 6 years ago)

Reply 59