*UNOFFICIAL MARK SCHEME* Edexcel Maths C1 2017

Ill stick to trapping

Question said that from week 12 onwards they produced the same number of bikes each week. Your method would be correct if they continued to produce a greater number of bikes on a weekly basis.

brb crying.

1) +C
2)a=1/16
3) a2 = 2k
a3 = k+1/2
k=17/6
4) d=6
10316 total
5) x=3 and x=-1
6) (x-4)^2+3
Minimum point at (4,3) intercept at (0,19)
PQ : 4sqrt(17) units
7)
8) 5x-4y-49=0
Area = 369/10
9) line theough (0,C)
Asymptote at y= 5
equate and disciminant greater than 0
c<5-2sqrt(3) and c> 5+sqrt(3)
10) k = 75
c = 5/2
just differentiate
x = -5/3

(some questions might be missing; reply with edits)

na just ran it through with calculator we got all method marks for sure we just made small mistake with denominators answer was 369/10

Hopefully you get method marks

Ill stick to trapping

Just seen the mark scheme turns out I didn't get 100%🤣

how did you get 10316??? i did 52/2(140+140+51(6)) for the total number of bikes?

f(x) = (2x-5)^2 * (x+3)
f(0) = (2(0)-5)^2 * (0+3)
= (-5)^2 * (3)
= 25 * 3 = 75
Therefore f(0) - k = 0, 75 - k = 0 => k = 75.

I think your answer to question 3 is wrong. For a3 i got 2k^2+k
And so my k was different k=3/2