Official AS and A2 Level Edexcel Chemistry 2017 (OLD SPEC)

Did you get 1,1,4 di ethyl something?
And for H-F bonds highly exo did you say
HF are strong and others are weak 😫?
And lastly for isomer did you get 2 methyl prop1ene?

I just remembered one, which one did you put for high bp and mp?? I think I put covalent or ionic

Yeah that was 100% ionic and covalent
For now, in section A I know I got first 10 marks all right, but I think I got 3/20 wrong, the copper chromium colour, the naming with octane probably and let's say another random one I don't remember, but I was 100% sure for like 15/20

Oh yeah, last thing about section A,
What did you put for enthalpy?! There were answers like +25, -25, +60, -60

Oh yeah, last thing about section A,
What did you put for enthalpy?! There were answers like +25, -25, +60, -60

I remember getting +25 for this but I don't remember what the question was asking

Yeah I got same formula, and displayed was 2 double bonds,
For low heat capacity and polystyrene cup I put less heat loss therefore temp increase would be more accurate? And low heat capacity therefore ewuipment would absorb less heat and some other stuff,
Emphieical formula was 2:2:3 for Na question
And empirical for Allene was CH2 and formula for CnH2n?

Struggled a bit with the last question, didn't realise there were 2 double bonds until I drew it out. Glad someone else got that. Also got 223 for Na empirical question, I almost crossed it out thinking I was wrong. Thank God I didn't.

For the question how you measure lattice energy, did you guys put born-Haber cycle?? I stupidly spelt it as borne-haber do you think I'd still get the mark😂😂

Struggled a bit with the last question, didn't realise there were 2 double bonds until I drew it out. Glad someone else got that. Also got 223 for Na empirical question, I almost crossed it out thinking I was wrong. Thank God I didn't.

For the question how you measure lattice energy, did you guys put born-Haber cycle?? I stupidly spelt it as borne-haber do you think I'd still get the mark😂😂

There are not double bonds. The compound formed is c10h18.... a single bond between two card free radicals on each of the free radical cyclo pentanes

But it's a termination reaction, free radicals get used up

Yeah the 2 free radicals react together to form 1 single bond between 2 carbons

If you simplify it then imagine its 2 ch3 radicals binding together..... you for c2h6 which has all single bonds

What did you guys put for the first stage in the process of converting crude oil to pentane??

I wrote fractional distillation but that's obviously wrong )))