spring problem M2
Hi
A point A of the ceiling is directly above a point B of the floor 2.5 meters below. A and B are joined by a light spring of natural length 2 meters; the tension in the spring is then 20 newtons. A Lump of Putty of weight 4 newtons is now attached to the spring at the point 1 meter above the floor. At what height above the floor will the Putty rest in equilibrium?
A point A of the ceiling is directly above a point B of the floor 2.5 meters below. A and B are joined by a light spring of natural length 2 meters; the tension in the spring is then 20 newtons. A Lump of Putty of weight 4 newtons is now attached to the spring at the point 1 meter above the floor. At what height above the floor will the Putty rest in equilibrium?
Original post by Deffect
Hi
A point A of the ceiling is directly above a point B of the floor 2.5 meters below. A and B are joined by a light spring of natural length 2 meters; the tension in the spring is then 20 newtons. A Lump of Putty of weight 4 newtons is now attached to the spring at the point 1 meter above the floor. At what height above the floor will the Putty rest in equilibrium?
A point A of the ceiling is directly above a point B of the floor 2.5 meters below. A and B are joined by a light spring of natural length 2 meters; the tension in the spring is then 20 newtons. A Lump of Putty of weight 4 newtons is now attached to the spring at the point 1 meter above the floor. At what height above the floor will the Putty rest in equilibrium?
I can't make head nor tail of your first working.
Re the second working.
You know enough to work out e and v.
For v.
The spring has been stretched from 2 to 2.5 metres.
The putty is 1.5 metres below A, ie. 1/5/2.5 = 0.6 of the spring's stretched length. So, the natural length of the upper part is the same proportion of the spring's natural length, ie. 0.6, so corresponding natural length is 0.6 x 2 m.
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