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Stuck on a maths question

3^5/2 - 3^1/2

How would you do this?
The 5/2 and 1/2 are fractional indices
Reply 1
Can u spot any common factors?
Reply 2
Original post by iloading22
3^5/2 - 3^1/2

How would you do this?
The 5/2 and 1/2 are fractional indices


The general rule for a fractional power is that xab=xbax^{\frac{a}{b}}=\sqrt[b]{x}^a

Use that rule to convert the sum into more manageable terms and simplify from there!
(edited 6 years ago)
Original post by Ed5
The general rule for a fractional power is that xab=xabx^{\frac{a}{b}}=\sqrt[a]{x}^b


Please keep full solutions out of your responses. Help with hints only.
Original post by RDKGames
Please keep full solutions out of your responses. Help with hints only.


Maybe that's how he wanted to help
Original post by Reece.W.J
Maybe that's how he wanted to help


Too bad then because the situation doesn't require a last resort

https://www.thestudentroom.co.uk/showthread.php?t=4854040#post73059680
Original post by RDKGames
Too bad then because the situation doesn't require a last resort

https://www.thestudentroom.co.uk/showthread.php?t=4854040#post73059680


Idk what that link was for but I couldn't view it or it had been removed for some reason
Original post by Reece.W.J
Idk what that link was for but I couldn't view it or it had been removed for some reason


Posting Guidelines thread at the very top of the forum.

Spoiler

Reply 8
I've edited out the solution, my bad!
Reply 9
Original post by Ed5
The general rule for a fractional power is that xab=xabx^{\frac{a}{b}}=\sqrt[a]{x}^b

Use that rule to convert the sum into more manageable terms and simplify from there!


xab(xb)a \displaystyle x^{\frac{a}{b}} \equiv {(\sqrt[b]{x})}^a
(edited 6 years ago)
Reply 10
Original post by Desmos
xab(xb)a \displaystyle x^{\frac{a}{b}} \equiv {(\sqrt[b]{x})}^a


**** I literally said the rule in my head and still wrote it wrong, thanks 😅
3^(5/2) - 3^(1/2)

count 3^(1/2) as x
3^(5/2) is x^5

so the one above is x^5-x and we can factorize it using x
Too much hint already!

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