Ultrasound Waves Homework Question
Physics Question (https://imgur.com/gallery/CeD7R)
Hello. I've got this exam-style question for my Physics homework. As you can see, the question asks for the thickness of the bone by using the graph, data provided and the d=s x t equation.
If made the calculations that the space between the two peaks is 17µm-13µm=4µm.
Then converted into metres : =4x10^-6 m
Using the equation "Distance = Speed x Time": 3750 x (4x10^-6 )=0.015m
However, 0.015m - or 1.5cm - seems quite unrealistic for the thickness of a bone. I might also have made a few errors along the way with regards to calculation. Can someone help me?
Hello. I've got this exam-style question for my Physics homework. As you can see, the question asks for the thickness of the bone by using the graph, data provided and the d=s x t equation.
If made the calculations that the space between the two peaks is 17µm-13µm=4µm.
Then converted into metres : =4x10^-6 m
Using the equation "Distance = Speed x Time": 3750 x (4x10^-6 )=0.015m
However, 0.015m - or 1.5cm - seems quite unrealistic for the thickness of a bone. I might also have made a few errors along the way with regards to calculation. Can someone help me?
Original post by Adam14701470
Physics Question (https://imgur.com/gallery/CeD7R)
Hello. I've got this exam-style question for my Physics homework. As you can see, the question asks for the thickness of the bone by using the graph, data provided and the d=s x t equation.
If made the calculations that the space between the two peaks is 17µm-13µm=4µm.
Then converted into metres : =4x10^-6 m
Using the equation "Distance = Speed x Time": 3750 x (4x10^-6 )=0.015m
However, 0.015m - or 1.5cm - seems quite unrealistic for the thickness of a bone. I might also have made a few errors along the way with regards to calculation. Can someone help me?
Hello. I've got this exam-style question for my Physics homework. As you can see, the question asks for the thickness of the bone by using the graph, data provided and the d=s x t equation.
If made the calculations that the space between the two peaks is 17µm-13µm=4µm.
Then converted into metres : =4x10^-6 m
Using the equation "Distance = Speed x Time": 3750 x (4x10^-6 )=0.015m
However, 0.015m - or 1.5cm - seems quite unrealistic for the thickness of a bone. I might also have made a few errors along the way with regards to calculation. Can someone help me?
Sounds quite realistic to me tbh- I'd be worried if it was coming out at 15cm or 1.5mm
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