Urgent CHEM Question ..

God, this is killing me. I can't do it lol.

Please help me on this question:

An acid, H2X, reacts with sodium hydroxide as shown in the equation below.

H2X(aq) + 2NaOH(aq) →2Na+(aq) + X2–(aq) + 2H2O(l)
A solution of this acid was prepared by dissolving 1.92 g of H2X in water and makingthe volume up to 250 cm3 in a volumetric flask.

A 25.0 cm3 sample of this solution required 21.70 cm3 of 0.150 mol dm–3 aqueous NaOH for complete reaction.

Now, I've figured the number of moles in the NaOH which is 3.26e-3 and the number of moles of the H2X in 25.0cm is 1.63e-3

What is the number of moles of H2X in 1.92g?