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Parametric to Cartesian equation

Bit confused with this question:

x=sec(theta) , y=ln(1+cos(2theta))

Find a Cartesian equation in the form f(x)g(y)=2
Usually I would isolate theta and sub it into the y equation but I'm not sure that works in this situation.

If I did that i would get theta = arcsec(x) but then substituting this into the other equation is a bit confusing. Is this correct?
Reply 1
Original post by ElDonCorleone
Bit confused with this question:

x=sec(theta) , y=ln(1+cos(2theta))

Find a Cartesian equation in the form f(x)g(y)=2
Usually I would isolate theta and sub it into the y equation but I'm not sure that works in this situation.

If I did that i would get theta = arcsec(x) but then substituting this into the other equation is a bit confusing. Is this correct?


Remember your trig identities. You can replace the 1+cos(2theta) with cos2(theta) and turn x=sec(theta) into x = 1/cos(theta)

Try and rearrange y=ln(cos2(theta))
(edited 6 years ago)
Reply 2
Original post by BDunlop
Remember you'r trig identities. You can replace the 1+cos(2theta) with cos2(theta) and turn x=sec(theta) into x = 1/cos(theta)

Try and rearrange y=ln(cos2(theta))


Oh of course of course... thanks a lot !

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