Proof by contradiction appropriate?
I had an exam question that went like:
"Prove that, for all real numbers:
x^2 + 2Px + q^2 - p^2 = 0
Other people who did the exam used the discriminant but I used proof by contradiction. Is this appropriate?
i.e.
Assume it is wrong and then find a counterexample instead.
"Prove that, for all real numbers:
x^2 + 2Px + q^2 - p^2 = 0
Other people who did the exam used the discriminant but I used proof by contradiction. Is this appropriate?
i.e.
Assume it is wrong and then find a counterexample instead.
Original post by Seppuku
I had an exam question that went like:
"Prove that, for all real numbers:
x^2 + 2Px + q^2 - p^2 = 0
Other people who did the exam used the discriminant but I used proof by contradiction. Is this appropriate?
i.e.
Assume it is wrong and then find a counterexample instead.
"Prove that, for all real numbers:
x^2 + 2Px + q^2 - p^2 = 0
Other people who did the exam used the discriminant but I used proof by contradiction. Is this appropriate?
i.e.
Assume it is wrong and then find a counterexample instead.
""Prove that, for all real numbers: x^2 + 2Px + q^2 - p^2 = 0" doesn't make any sense. Since you mentioned the discriminant, presumably the question mentioned something about the number of roots. Please post the complete question so that I can help you further.
Original post by Seppuku
I had an exam question that went like:
"Prove that, for all real numbers:
x^2 + 2Px + q^2 - p^2 = 0
Other people who did the exam used the discriminant but I used proof by contradiction. Is this appropriate?
i.e.
Assume it is wrong and then find a counterexample instead.
"Prove that, for all real numbers:
x^2 + 2Px + q^2 - p^2 = 0
Other people who did the exam used the discriminant but I used proof by contradiction. Is this appropriate?
i.e.
Assume it is wrong and then find a counterexample instead.
Proof by contradiction isn't really about finding a counterexample, but more generally a contradiction of any kind.
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