Hi I was just wondering if someone could help me out with this moles question:
When heated copper oxide reacts with gaseous ammonia to form copper;
2CuO(s) + 2NH3(g) → 2Cu(s) + N2(g) + 3H2O(g)
If the reaction takes place to completion using ammonia and an excess of copper oxide, which of the following will be found?
A) At 400 C, the volume of the products will be twice the volume of the
ammonia that was used
B) If the reaction is cooled to room temperature, the volume of the products will be half the volume of ammonia that was used
C) The amount in mol of copper obtained will be half the amount in mol of copper oxide that was used
I understand why A and C are incorrect but I just don't understand how you could work out B...