# Maths Evaluate Question

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(Original post by

What do you mean by the second part?

**mqb2766**)What do you mean by the second part?

This is the question

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(Original post by

Which part are you having trouble with? It looks straightforward.

**mqb2766**)Which part are you having trouble with? It looks straightforward.

My answer was n^(n-1) + 5 but apparently this is wrong.

The question after is simple as well but I can’t do it either. It was sin(t) with the text below saying t = pi.

Apparently the answer can’t be cos(pi) as it must be an integer or decimal so I put zero as well but apparently that was wrong too. Maybe I’m just answering them wrong?

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#6

(Original post by

Well, haven’t really done any evaluation like this at A-Level.

My answer was n^(n-1) + 5 but apparently this is wrong.

The question after is simple as well but I can’t do it either. It was sin(t) with the text below saying t = pi.

Apparently the answer can’t be cos(pi) as it must be an integer or decimal so I put zero as well but apparently that was wrong too. Maybe I’m just answering them wrong?

**Ogaar**)Well, haven’t really done any evaluation like this at A-Level.

My answer was n^(n-1) + 5 but apparently this is wrong.

The question after is simple as well but I can’t do it either. It was sin(t) with the text below saying t = pi.

Apparently the answer can’t be cos(pi) as it must be an integer or decimal so I put zero as well but apparently that was wrong too. Maybe I’m just answering them wrong?

You must have covered this.

Last edited by mqb2766; 1 month ago

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#7

Notation means: "find d/dx for the expression, the final answer is what you get when you substitute x=1 into that expression".

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Notation means: "find d/dx for the expression, the final answer is what you get when you substitute x=1 into that expression".

**DFranklin**)Notation means: "find d/dx for the expression, the final answer is what you get when you substitute x=1 into that expression".

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(Original post by

How do you differentiate x^2, x^3, ..., x^n? Spot the pattern. Then 1^(n-1) =...

You must have covered this.

**mqb2766**)How do you differentiate x^2, x^3, ..., x^n? Spot the pattern. Then 1^(n-1) =...

You must have covered this.

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**DFranklin**)

Notation means: "find d/dx for the expression, the final answer is what you get when you substitute x=1 into that expression".

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#13

(Original post by

Where have you only got 1 from? Surely it’s n^(n-1). If it’s 1 then overall obviously it equals 1 + 5 = 6 but that’s not correct...

**Ogaar**)Where have you only got 1 from? Surely it’s n^(n-1). If it’s 1 then overall obviously it equals 1 + 5 = 6 but that’s not correct...

Where is the x term in your expression n^(n-1)? Is this before or after you sub x=1.

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(Original post by

What is the derivative of x^3?

Where is the x term in your expression n^(n-1)? Is this before or after you sub x=1

**mqb2766**)What is the derivative of x^3?

Where is the x term in your expression n^(n-1)? Is this before or after you sub x=1

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#15

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Oh I get you now man. I’m being stupid. Anything multiplied by 1 is 1. So 1^n-1 is 1... but how come the answer isn’t 6 then? I’ve tried that before.

**Ogaar**)Oh I get you now man. I’m being stupid. Anything multiplied by 1 is 1. So 1^n-1 is 1... but how come the answer isn’t 6 then? I’ve tried that before.

What is the derivative before you sub x=1?

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#17

(Original post by

nx^(n-1) + 5

**Ogaar**)nx^(n-1) + 5

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(Original post by

Ok so sub x=1 and remember there are two operations in the first term: multiplication and power.

**mqb2766**)Ok so sub x=1 and remember there are two operations in the first term: multiplication and power.

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#19

(Original post by

You end up with the indice not having an effect first, since 1 to the power of anything is 1. Then you just have nx + 5, which isn’t the correct answer btw

**Ogaar**)You end up with the indice not having an effect first, since 1 to the power of anything is 1. Then you just have nx + 5, which isn’t the correct answer btw

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(Original post by

Why x in that expression? You've replaced it with 1?

**mqb2766**)Why x in that expression? You've replaced it with 1?

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