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please help

its important
https://imgur.com/0dtxWae

am giving the data of number of moles of the respective species at equilibrium N204=7.3 and NO2=5.4 so clearly N204 has more moles than NO2 but if you increase pressure you will expect the equilibrium to shift to left thats according to mole ratio which says there are fewer moles on reactant side so equilibrium must shift to left but the actual moles of reactant is greater than the product so how is this valid? here is the link to the sample material paper--https://qualifications.pearson.com/content/dam/pdf/International%20Advanced%20Level/Chemistry/2018/Specification-and-Sample-Assessment/International-A-Level-Chemistry-SAMs.pdf
(edited 3 years ago)
Reply 1
Original post by riamu
its important
https://imgur.com/0dtxWae

am giving the data of number of moles of the respective species at equilibrium N204=7.3 and NO2=5.4 so clearly N204 has more moles than NO2 but if you increase pressure you will expect the equilibrium to shift to left thats according to mole ratio which says there are fewer moles on reactant side so equilibrium must shift to left but the actual moles of reactant is greater than the product so how is this valid? here is the link to the sample material paper--https://qualifications.pearson.com/content/dam/pdf/International%20Advanced%20Level/Chemistry/2018/Specification-and-Sample-Assessment/International-A-Level-Chemistry-SAMs.pdf


When working out which direction an equilibrium will shift when you change the pressure, you consider the number of mol of particles in the balanced equation (in this case it is a 1:2 ratio), rather than the the number of mol of chemicals present in the equilibrium mixture.
Reply 2
Original post by Pigster
When working out which direction an equilibrium will shift when you change the pressure, you consider the number of mol of particles in the balanced equation (in this case it is a 1:2 ratio), rather than the the number of mol of chemicals present in the equilibrium mixture.

but why is that the case why not consider the actual moles at equilibrium?
Reply 3
Original post by riamu
but why is that the case why not consider the actual moles at equilibrium?

Pressure is caused by gas particles banging into the walls of the container. The more particles there are, the more collisions and hence the higher the pressure.

Consider A <-> 2B

If you have 10A and 4B in a mixture, that's 14 particles in total.

If you're right and you increase P (by making the container smaller), since there are more A particles (10 vs 4), then the forward reaction would happen. If 1 A converts into 2B, we now have 9A and 6B. We now have 15 particles, i.e. P has further increased.

If I'm right and you increase P, the backwards reaction occurs and we end up with 11A and 2B. You know I'm right.

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