Hedwigeeeee
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I sketched the graph and plotting in numbers to get the answer correctly,are there better methods?Attachment 1031736
Last edited by Hedwigeeeee; 3 weeks ago
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mqb2766
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(Original post by Hedwigeeeee)
I sketched the graph and plotting in numbers to get the answer correctly,are there better methods?Attachment 1031736
Can you try uploading again, the attachment isnt found.
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Hedwigeeeee
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(Original post by mqb2766)
Can you try uploading again, the attachment isnt found.
Name:  IMG_20210924_091500-compressed.jpg.jpeg
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Size:  30.5 KBsorry in my phone is has been uploaded...i tried again and are u able to find it now?
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mqb2766
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(Original post by Hedwigeeeee)
Name:  IMG_20210924_091500-compressed.jpg.jpeg
Views: 8
Size:  30.5 KBsorry in my phone is has been uploaded...i tried again and are u able to find it now?
I think they wanted you to think about z in mod-arg form, so z^3 has the modulus cubed and the arg tripled. So its fairly easy to see
|z|>1
and by thinking about what happens when you triple the boundary of each quadrant (0-90, 90-180, ...) its easy to see z cant lie in the first quadrant if 360 > arg(z^3) > 315, but could lie in the 2nd, 3rd, 4th.
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