Mathswatch help

https://www.flickr.com/photos/198117005@N06/52813094668/in/dateposted-public/

Can someone please help, I don't know what I'm doing wrong. The question is attached in the link.

https://www.flickr.com/photos/198117005@N06/52813094668/in/dateposted-public/

Can someone please help, I don't know what I'm doing wrong. The question is attached in the link.

Can you tell us what you wrote ? Mathswatch is very fussy

Q) The base of an open rectangular box is the length (2x+7) cm and width x cm
The area of this base is 57cm²
The height of the open box is (x-1) cm.
Show that 2x²+7x-57=0


x(2x+7)=57 (I get 1 mark for doing this bit)
2x²+7x=57
2x²+7x-57=0 (These two steps don't count for the 2 mark)

Yes I could see that - where have you lost the marks?

When I do this part:
2x²+7x=57
2x²+7x-57=0

Have you tried putting spaces in 2x^2 + 7x - 57 = 0 [it could be something as silly as this]

Yes I have but it's not working.

Spaces between each term and the + and - and = and the 0?

Can you screenshot that?

Spaces between each term and the + and - and = and the 0?

Can you screenshot that?

The screenshot is taking a while to upload because it's being moderated but I'll tell you what I've put down into Mathswatch. It doesn't change anything though.

(2x + 7) (x) = 57
2x² + 7x = 57
2x² + 7x - 57 = 0

This is why we don't use Mathswatch ... did you try adding Hence .... as required.