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Maths Q

Hey, can anyone please help me with this question? Not sure if I’m on the right track. If I am, I’m not sure how to work out the length EB

Thanks D08BA58A-D221-4B7D-BDA8-B4D46FC7B1D9.jpg.jpeg
Original post by subbhy
Hey, can anyone please help me with this question? Not sure if I’m on the right track. If I am, I’m not sure how to work out the length EB

Thanks D08BA58A-D221-4B7D-BDA8-B4D46FC7B1D9.jpg.jpeg


Looks good so far. Now you need to find the length of EB. Pythagoras, twice.
(edited 8 months ago)
Reply 2
Original post by _Boomerang
Looks good so far. Now you need to find the length of EB. Pythagoras, twice.


Work out FB and then use FB and FE?
Original post by subbhy
Work out FB and then use FB and FE?

Yes, that will work. You don't actually need FB. Working out FB^2 is enough. You can do the whole calculation in one go if you like. You will end up with something of the form EB=a2+b2+c2EB=\sqrt{a^2+b^2+c^2}.
Reply 4
Original post by _Boomerang
Yes, that will work. You don't actually need FB. Working out FB^2 is enough. You can do the whole calculation in one go if you like. You will end up with something of the form EB=a2+b2+c2EB=\sqrt{a^2+b^2+c^2}.


Ah ok gotcha thanks a lot

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