A level maths help
Find the set of values of a for which the equation
ax2 + 3x+ 2 = 0
has two distinct roots.
ax2 + 3x+ 2 = 0
has two distinct roots.
(edited 6 months ago)
I did ax2 +3x +2 =0
b2 -4ac=0
so (3x)2 - 4 x a x2
9x2 - 8a =0
but i don't know what to do next
b2 -4ac=0
so (3x)2 - 4 x a x2
9x2 - 8a =0
but i don't know what to do next
Original post by user987789
I did ax2 +3x +2 =0
b2 -4ac=0
so (3x)2 - 4 x a x2
9x2 - 8a =0
but i don't know what to do next
b2 -4ac=0
so (3x)2 - 4 x a x2
9x2 - 8a =0
but i don't know what to do next
Couple of things:
* The discriminant doesn't include any "x" or "x^2" terms.
* Discriminant = 0 is the condition for two equal roots, not two distinct roots.
Original post by old_engineer
Couple of things:
* The discriminant doesn't include any "x" or "x^2" terms.
* Discriminant = 0 is the condition for two equal roots, not two distinct roots.
* The discriminant doesn't include any "x" or "x^2" terms.
* Discriminant = 0 is the condition for two equal roots, not two distinct roots.
Okay so,
ax2 +3x +2 >0
b^2 -4ac> 0
3^2 - 4 x a x2>0
9 -8a >0
9 - 8 > a
1 > a
is that correct?
Original post by user987789
Okay so,
ax2 +3x +2 >0
b^2 -4ac> 0
3^2 - 4 x a x2>0
9 -8a >0
9 - 8 > a
1 > a
is that correct?
ax2 +3x +2 >0
b^2 -4ac> 0
3^2 - 4 x a x2>0
9 -8a >0
9 - 8 > a
1 > a
is that correct?
9 - 8a > 0 is correct, but you've gone wrong after that. Try adding 8a to both sides.
Original post by old_engineer
9 - 8a > 0 is correct, but you've gone wrong after that. Try adding 8a to both sides.
9 -8a >0
9> 8a
9/8 > a
is that right?
Original post by user987789
9 -8a >0
9> 8a
9/8 > a
is that right?
9> 8a
9/8 > a
is that right?
Yes that's correct, although you'd normally present the answer as a < 9/8
Original post by old_engineer
Yes that's correct, although you'd normally present the answer as a < 9/8
Thank you so much, so I don't need two solutions for these types of questions?
Original post by user987789
Thank you so much, so I don't need two solutions for these types of questions?
There’s only one range for this question. But you need to consider other questions on a case by case basis.
Original post by user987789
Thank you so much, so I don't need two solutions for these types of questions?
One thing you need to consider seperately is a=0, as its not a quadratic in that case so the discriminant analysis doesnt apply.
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