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isaac physics Lorentz Transform 1

i have tried for ages and just cant do it

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Reply 1
Original post by sam3541654
i have tried for ages and just cant do it

Which one and what have you tried?
Reply 2
it is w=sqrt(wx^2+wy^2)
Reply 3
Original post by sam3541654
it is w=sqrt(wx^2+wy^2)

Youve got to work through and simplify the expressions. The end result (in terms of v, c or theta) is relatively simple
Reply 4
hi ive also been trying this, what have you got so far?
Reply 5
Reply 6
Original post by panda34678
hi ive also been trying this, what have you got so far?

i honestle dont know but when i try submit the answer its incorrect
Reply 7
Original post by sam3541654

Not showing for me. You need to upload it to another site to share the image, then link it.
Reply 9
It helps to see the working but from a quick glance it looks about right. Id use the pythagorean identity on
v^2sin^2(theta)
and things should factorise / cancel. If not, upload your full working.
Reply 10
Original post by mqb2766
It helps to see the working but from a quick glance it looks about right. Id use the pythagorean identity on
v^2sin^2(theta)
and things should factorise / cancel. If not, upload your full working.

i dont understand how to use it as i have v^2sin^2(theta) and a 2cvcos(theta)
Reply 11
Original post by sam3541654
i dont understand how to use it as i have v^2sin^2(theta) and a 2cvcos(theta)

sin^2 = 1 - cos^2
so ....
Reply 12
yeah sorry you have completely lost me i dont think i have been taught that rule and how t use it
Reply 13
Original post by sam3541654
yeah sorry you have completely lost me i dont think i have been taught that rule and how t use it

Its just pythagoras, if youre trying to do a question with trig/algebraic simplification you should have covered it. So
sin^2(theta) + cos^2(theta) = 1
so multply through by v^2, sub for v^2sin^2(theta) and ....
I have got c^2 +v^2cos^2(theta) - 2 v c cos(theta) divided by c- vcos(theta) but can't seem to simplify any further, can anyone help where I went wrong?
Reply 15
what does multiply though mean ???
Reply 16
Original post by panda34678
I have got c^2 +v^2cos^2(theta) - 2 v c cos(theta) divided by c- vcos(theta) but can't seem to simplify any further, can anyone help where I went wrong?

Factorize the numerator (and then simplify the fraction) so
c^2 - 2 c v cos(theta) + v^2cos^2(theta)
Ive reordered it.
(edited 5 months ago)
Original post by mqb2766
Factorize the left hand side (and then simplify the fraction) so
c^2 - 2 v c cos(theta) + v^2cos^2(theta)
Ive reordered it.

so you get c-2 +vcos(theta) ?
Reply 18
so when simplified u end up with just c
Reply 19
Original post by sam3541654
so when simplified u end up with just c

Have you tried entering it?

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