It helps to see the working but from a quick glance it looks about right. Id use the pythagorean identity on
v^2sin^2(theta)
and things should factorise / cancel. If not, upload your full working.

Reply 10

sam3541654

Original post by mqb2766

It helps to see the working but from a quick glance it looks about right. Id use the pythagorean identity on
v^2sin^2(theta)
and things should factorise / cancel. If not, upload your full working.

i dont understand how to use it as i have v^2sin^2(theta) and a 2cvcos(theta)

Reply 11

mqb2766

Original post by sam3541654

i dont understand how to use it as i have v^2sin^2(theta) and a 2cvcos(theta)

sin^2 = 1 - cos^2
so ....

Reply 12

sam3541654

yeah sorry you have completely lost me i dont think i have been taught that rule and how t use it

Reply 13

mqb2766

Original post by sam3541654

yeah sorry you have completely lost me i dont think i have been taught that rule and how t use it

Its just pythagoras, if youre trying to do a question with trig/algebraic simplification you should have covered it. So
sin^2(theta) + cos^2(theta) = 1
so multply through by v^2, sub for v^2sin^2(theta) and ....

Reply 14

panda34678

I have got c^2 +v^2cos^2(theta) - 2 v c cos(theta) divided by c- vcos(theta) but can't seem to simplify any further, can anyone help where I went wrong?

Reply 15

sam3541654

what does multiply though mean ???

Reply 16

mqb2766

Original post by panda34678

I have got c^2 +v^2cos^2(theta) - 2 v c cos(theta) divided by c- vcos(theta) but can't seem to simplify any further, can anyone help where I went wrong?