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C3: Differentiation

I had to differentiate x3(2x+6)4x^3(2x+6)^4

I got down to 8x3(2x+6)3+3x2(2x+6)48x^3(2x+6)^3 + 3x^2(2x+6)^4

According to the solution bank this is correct but you have to simplify it down afterwards to 2x2(2x+6)3(7x+9)2x^2(2x+6)^3(7x+9)

Anyone can explain how that works please?
Reply 1
Your expression contains two terms and both (2x+6)3(2x+6)^3 and x2x^2 are factors of both of them. That means we can take (2x+6)3(2x+6)^3 and x2x^2 outside the expression:

x2(2x+6)3[8x+3(2x+6)]\displaystyle x^2(2x+6)^3 \left[8x+3(2x+6)\right]

Does this make sense and can you finish the simplification?
Reply 2
Original post by notnek
Your expression contains two terms and both (2x+6)3(2x+6)^3 and x2x^2 are factors of both of them. That means we can take (2x+6)3(2x+6)^3 and x2x^2 outside the expression:

x2(2x+6)3[8x+3(2x+6)]\displaystyle x^2(2x+6)^3 \left[8x+3(2x+6)\right]

Does this make sense and can you finish the simplification?


Why does the 8x go into the bracket with the higher power?
Reply 3
Original post by Sarabande
Why does the 8x go into the bracket with the higher power?

I don't really understand your question. Could you try to explain again?

Try expanding the expression that I posted and you should see that it is equal to the two terms in your derivative.
Reply 4
I gave it a little thought. It makes perfect sense now. Thanks.

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