A block of timber 130 mm thick is floating in water with 62 mm submerged below the water surface. Assuming the density of water to be 1000 kg/m3 and the acceleration due to gravity to be 9.81m/s2, calculate the density of the timber block (in kg/m3)
I'm stuck on this question.
I've worked out that Upthrust=pvg (where p is density, v is volume and g is acceleration due to gravity). Therefore the weight of displaced fluid= weight of object since it is floating:
p(object) x V(object)=p(fluid) x V(fluid) [the g constants on both sides cancel out]
p(fluid) is 1000
so p(object)xV(object)=1000 x V(fluid)
I'm not sure what to do from here, since we don't know all 3 side lengths of the object to work out the volume of the fluid..?