The Official Edexcel FP2 Thread 6th June 2014

TheInfidel

1

Post you're revision stuff here etc...

Reply 1

Wilsoncw1997

13

I have bad feelings for this exam

Reply 2

forsparta

This exam is one of my secure exams, looking forward to it!
It is really annoying that it happens to be clamped inbetween both my economics exams, econ and maths don't go well together

Reply 3

mappostolova

What are your predictions for this paper...

Do you have feelings for the sort of questions that may come up?

Reply 4

p.khan

Help please!!!
This is so stupid because its only one mark but I really don't understand how its done.

Part a was fine (X<-2, -5<X<-3) but I couldn't get b (mark scheme says X>-2)

I know I'm probably just missing something so easy but I'd really appreciate it if someone could clear thimgs up a bit...

Posted from TSR Mobile

Reply 5

ThatManAlex

Original post by p.khan

Help please!!!
This is so stupid because its only one mark but I really don't understand how its done.

Part a was fine (X<-2, -5<X<-3) but I couldn't get b (mark scheme says X>-2)

I know I'm probably just missing something so easy but I'd really appreciate it if someone could clear thimgs up a bit...

Posted from TSR Mobile

OK, I just did the question, first of all I think you meant for part a that X>-2, not less than -2 :smile:

And for part b, I drew a graph of 2/[x+3] and x+4, and then the only place they intersected was at x=-2. (Because it was a MOD graph for 2/[x+3], it meant it was only the positive values of y). This meant that because x+4 was greater than 2/[x+3], x had to be greater than -2. X>-2.

I attempted to draw it on paint :smile:

fp2 graph.jpg22.1KB

Reply 6

p.khan

Original post by ThatManAlex

OK, I just did the question, first of all I think you meant for part a that X>-2, not less than -2 :smile:

And for part b, I drew a graph of 2/[x+3] and x+4, and then the only place they intersected was at x=-2. (Because it was a MOD graph for 2/[x+3], it meant it was only the positive values of y). This meant that because x+4 was greater than 2/[x+3], x had to be greater than -2. X>-2.

I attempted to draw it on paint :smile:

My mistake, I did mean x>-2

I completely forgot about sketching the graphs but I see how its done now. I think I got confused beacuse I did part a by comining the 2 fractions rather than sketching (as that is a weak point of mine!!). And then tried to use that for part b, which is where I went wrong I guess.

But anyway, thanks for clearing that up - :awesome:

Posted from TSR Mobile

Reply 7

aminkaram

Hey guys. I think a useful thing to do this close to the exam is to share exam techniques.How you can check answers etc... does anyone have any pointers? I would say one obvious thing would be to check complex numbers and Series questions on your calculator once you get answers. And for inequalities and loci you can test a few numbers to make sure your equation works.

Anyone else got tips?

Reply 8

marios50

1

Well considering (6) as a troublesome question, the rest were not THAT bad. The integration in the last question required the knowledge of tan^2x = 1 + sec^2x...

Reply 9

mrdw

Did the differential equation have a particular intergral of something like 27/10e... ? Transformation part b) no idea on that one

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Reply 10

johnj0061

Original post by mrdw

Did the differential equation have a particular intergral of something like 27/10e... ?

I got 3e^(-x)

Reply 11

tamlmt628

What did you get for the series expansion question ?

Reply 12

johnj0061

Original post by tamlmt628

What did you get for the series expansion question ?

3 + (1/6)x + (17/216)x^2
i wasn't confident though

I got the same

OP

Just found some solutions in another thread!!!

Thank them not me. :wink:

(but i forgot who it was lol)

Reply 15

aminkaram

That's correct! What did everyone get for the general solution of the first order differential?
I made so many silly mistakes on this paper and couldn't do the locus part b so I'm screwed really.

Reply 16

dadiamondz

8

Got the same - thought it looked wrong Though :/

Reply 17

BringerOfPie

4

Original post by johnj0061

3 + (1/6)x + (17/216)x^2
i wasn't confident though

looks correct to me

Reply 18

BringerOfPie

4

Original post by TheInfidel

Just found some solutions in another thread!!!

<image>

Thank them not me. :wink:

(but i forgot who it was lol)

4b is pi/18, pi/9, 7pi/18

not 5pi/18

pretty sure anyway

5a y = e^-3x (etc) looks like a copy error on your part

Was 7b finding f(x) as y^-3 = ... or as y = ... ?

6b was hard

edit: sorry for double post, pls dont kill

EDIT2: I MADE A MISTAKE WITH THE 4b

THE CORRECT ANSWERS ARE PI/18, 5PI/18, 7PI/18

PI/9 IS NOT CORRECT

(edited 9 years ago)

Reply 19

FLLF

for 6b did anyone get the radius was 5?

The Official Edexcel FP2 Thread 6th June 2014

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