Need help with this question ...
Stuck on this question ... Anybody can help ... Need working to be shown .. Many thanks in advance
Original post by Saj2830
Stuck on this question ... Anybody can help ... Need working to be shown .. Many thanks in advance
What sixth form course is this?
Similar triangles is a GCSE topic.
Cd/be = ac/bc
Original post by Arithmeticae
Cd/be = ac/bc
Can you please elaborate .... Thanks
Original post by Saj2830
Can you please elaborate .... Thanks
How much of an elaboration do you need - in similar triangles the ratio of corresponding sides is the same
21.6/12 = 1.8 = ac / bc
ac / 10 = 1.8
ac= 1.8 x 10 = 18
ac / 10 = 1.8
ac= 1.8 x 10 = 18
Original post by TenOfThem
How much of an elaboration do you need - in similar triangles the ratio of corresponding sides is the same
So ... X = 12.5 cm
Original post by Saj2830
So ... X = 12.5 cm
No, x = 8
18 - 10 = 8
Original post by Saj2830
So ... X = 12.5 cm
Not sure where you got that from
Can you see the 2 triangles
What is the enlargement factor from the small triangle to the large one?
Can you apply that to the length of 10 so you get the corresponding length in the large triangle?
Original post by Saj2830
So ... X = 12.5 cm
No, where did you get that from?
The scale factor between the triangle is 1.8...
Posted from TSR Mobile
(edited 9 years ago)
Original post by Arithmeticae
The scale factor between the triangle is 10...
The scale factor between the triangle is 10...
Original post by LouiseR1996
No, x = 8
18 - 10 = 8
18 - 10 = 8
Thank you
Original post by TenOfThem
Whoops, no idea what happened there. Major typo on my behalf
Posted from TSR Mobile
Original post by Saj2830
Thank you
Do you understand why?
Original post by TenOfThem
Do you understand why?
Yes , makes sense now ... Thanks all !!!
Original post by Saj2830
Yes , makes sense now ... Thanks all !!!
k
that's good then
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