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Original post by James Cameron
How to integrate cos^2 (4x) using double angle formula
As you have said ... Use double angle formula
Cos8x =
Original post by TenOfThem
As you have said ... Use double angle formula
Cos8x =
Cos8x =
i'm uncertain as to the steps required when there's a coefficient to the x
Original post by TenOfThem
As you have said ... Use double angle formula
Cos8x =
Cos8x =
Lol
Original post by James Cameron
i'm uncertain as to the steps required when there's a coefficient to the x
The same steps as with x on its own.
Original post by zetamcfc
The same steps as with x on its own.
What answer did you get
Original post by James Cameron
How to integrate cos^2 (4x) using double angle formula
Cos8x = 2cos^2(4x) - 1
So cos^2(4x) = (1/2)cos8x + (1/2)
Integrate that and you get (1/16)sin8x + (1/2)x + c
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Original post by James Cameron
What answer did you get
Can you do the question for cos^2x by using cos2x
If so .... This question is the same using cos8x
Original post by powelsmartin
Cos8x = 2cos^2(4x) - 1
So cos^2(4x) = (1/2)cos8x + (1/2)
Integrate that and you get (1/16)sin8x + (1/2)x + c
Posted from TSR Mobile
So cos^2(4x) = (1/2)cos8x + (1/2)
Integrate that and you get (1/16)sin8x + (1/2)x + c
Posted from TSR Mobile
Please do not post full solutions
Original post by TenOfThem
Please do not post full solutions
Apologies, I'm new to the forum - don't know all the rules yet!
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Original post by James Cameron
What answer did you get
Look at the other comments
Original post by powelsmartin
No problem .... The guidelines ask us to guide and prompt ... Giving solutions only as a last resort
Original post by powelsmartin
Cos8x = 2cos^2(4x) - 1
So cos^2(4x) = (1/2)cos8x + (1/2)
Integrate that and you get (1/16)sin8x + (1/2)x + c
Posted from TSR Mobile
So cos^2(4x) = (1/2)cos8x + (1/2)
Integrate that and you get (1/16)sin8x + (1/2)x + c
Posted from TSR Mobile
Thank you so much, could you also help me find the integral of
sin4xcos3x
Original post by James Cameron
What answer did you get
It is better for you to write your solution then others will check it, rather than give you the answers...
Original post by zetamcfc
It is better for you to write your solution then others will check it, rather than give you the answers...
OK i'll attempt to solve it now, thanks
Original post by James Cameron
Thank you so much, could you also help me find the integral of
sin4xcos3x
sin4xcos3x
Check your formula book first!
You should see a very useful formula for rewriting sinAcosB in terms of other things
Original post by James Cameron
Thank you so much, could you also help me find the integral of
sin4xcos3x
sin4xcos3x
Do you own a formula book? The formula to use is in there (For AQA at least).
Original post by zetamcfc
Do you own a formula book? The formula to use is in there (For AQA at least).
WHich formula would help here?
Original post by James Cameron
WHich formula would help here?
AS davros said, in a previous post...
Original post by zetamcfc
AS davros said, in a previous post...
Well i don't have a formula book on me right now, would the formula you're talking about be sin(a+b)=sinacosb+sinbcosa
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