Maybe a hint.
.
Comment: Perhaps a bit of working will help see why I do this. Remember our goal is to make all the x's to u's, and all the dx's into du's.
.
Comment: Perhaps a bit of working will help see why I do this. Remember our goal is to make all the x's to u's, and all the dx's into du's.
(edited 11 months ago)
Original post by tonyiptony
Maybe a hint.
.
Comment: Perhaps a bit of working will help see why I do this. Remember our goal is to make all the x's to u's, and all the dx's into du's.
.
Comment: Perhaps a bit of working will help see why I do this. Remember our goal is to make all the x's to u's, and all the dx's into du's.
I am still so stuck, sorry.
Original post by Matheen1
I am still so stuck, sorry.
Freebies first. Do the standard substitution step, so...
"Let u^2=x^2+3, (2u)du=(2x)dx".
We want to replace all the "x^2+3"s with "u^2", and the "(2x)dx" with "(2u)du". That's what we normally do in substitution, right?
But we don't have x^2+3 in the numerator... So make one with some finagling (see #2).
Then we should have something that's (much) easier to integrate.
(edited 11 months ago)
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