There were 2 calculations the first one was using mct and the other one was using the cycle with the arrows and the table provided ... So could someone tell me the answer of both ... Also, that skeletal compound he asked about what was its name and should we mention ( e/z) or not ?? , my answer was 3 methylhex3ene
First one was probably -3030.5 kJ/mol and the second one was -3509.1 kJ/mol. yeah thats the answer i didnt mention e/z either its not required
what was your answer to atom economy and % yield ?
mm same at first, but then i thought that each double bond can react with 2 hydrogens so i divided 4 by 2 getting 2
According to that question, 1 mole of the alkene reacts with 4 mole of hydrogen gas (H2), so in 4 mole of hydrogen gas, there are 8 hydrogen atoms. So, to hold 8 hydrogen atoms, 4 double bonds are needed.
Pretty sure I put the Br- lone pair. I hope it was butane, seriously don't want to get a B from an exam like this.
Do you remember the answer to this multiple-choice question: there were 3 compounds and a table of -ve values were given. I think they were copper sulphate, potassium something and potassium iodide.
How did you guys find the potassium Iodide question? The one where you were supposed to find the mass? I too didnt revise for equations. I definately got the Limewater and Co2 thing wrong. Hope grade boundaries are low.
Yeah most ppl made a mistake on that one....the answer for both the parts will be 0.33mol...and as jistification i wrote.."potassium iodide/potassium bromide is the limiting reagent which is why the moles of iodine can be found by comparing moles of potassium iodide and iodine."...i also wrote "0.5 moles of cl2 reacts with 1 mol of KI...but only 0.66mols of KI is present"....i no its too big for just one mark...but wth there was space and i didnt wanna compromise😛
Can someone tell me apart from dispersion force are there any more inter molecular forces on iodine mono chloride? And how did you guys drew the LCL3 ?