Gcse mole questions help!?!?!?

Start by using the equation:
mass = Mr * moles (you may/may not need to rearrange this)

So for the first question I would do 4 moles multiplied by 36.5g?

I think so, but not 100% sure

Thanks, but what about the last two question? You can't use that method I think

Remember Moles = Mass/Mr

Also, use the ratios in the equations!

Thanks, but what about the last two question? You can't use that method I think

Thanks, but what about the last two question? You can't use that method I think

for h I think you just work out the Mr of iron chloride, and since the ratio is 2:2, it is also 0.5:0.5, and so I think you halve the Mr to get your result?
(since you would have your Mr and multiply it by 0.5 moles)

OOOOOH good idea!
Thanks! I think I got it

I don't think you can use that method for questions e-i, what do you think?

e) for every molecule of ethanol... 2 molecules of CO2 are released
work out the moles of ethanol (mass/Mr) and then double it to get moles of CO2
and then mass = MrMol

i think

f) work out moles of water using moles = mass/ Mr and since 3H2O s are made for every one molecule of ethanol you divide it by 3 to get the moles of ethanol and then again mass = Mr Mol

g)same as above just mass is different

h) 1:1 mole ratio of Fe to FeCl3
so moles of FeCl3 is also 0.5
and then mass = Mr Moles

moles ratio of Fe and Cl2 = 2:3 so
use moles = Mass/ Mr to find moles of Fe and then divide them by 2 to get 1 moles and times it by 3 to get moles of Cl2 reacting

that's what I think anyway :3

if it's all wrong dont blame me x'D

You can use them!
e) C2H50H +302 > 2CO2 + 3H20
when 200g of ethanol is burned, what mass of CO2 is produced?
mass = 200, you can work out the mr, and using the ratio (1:3) and the mr (18) to work out the mass.

you can use this method for the rest of the questions

THANK YOU SO MUCH I TOTALLY GET IT NOW

All of your methods came to the answers I got, THANK YOU SO MUCH
*HUGS*