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Maths AS past paper questions (C1 and C2)

Could someone please help me with the following questions..:smile:


So I did (a) but couldn't solve (b) and (c)?


I couldn't solve this question.. :s-smilie:

This one too .. :frown:
f(x-1) =to the right 1
Reply 2
Original post by Adorable98
Could someone please help me with the following questions..:smile:


So I did (a) but couldn't solve (b) and (c)?


Write out u1 to u9 - what pattern can you spot?
Reply 3
Original post by Adorable98


This one too .. :frown:


You'll need to be more specific about this one.
Reply 4
Original post by Zacken
You'll need to be more specific about this one.


I don't know how to solve (a),(b)and (c) ??:frown:
Reply 5
Original post by Adorable98
I don't know how to solve (a),(b)and (c) ??:frown:


(a) is the cosine curve shifted pi/3 to the right; there's not much I can do to explain it, you should know your trig graphs and your function transformations.

(b) is just cosy=0\cos y = 0 (which you should know how to solve) and then back-substitute y=xπ3y = x - \frac{\pi}{3} and solve for xx.

(c) is just cosy=12\cos y = \frac{1}{\sqrt{2}} (Which you should know how to solve, one of the solutions is y=π4y = \frac{\pi}{4}) and then back-sub and solve for xx.

Perhaps you need to work on your concepts more before moving on to past papers? :redface:
Original post by Adorable98
Could someone please help me with the following questions..:smile:


So I did (a) but couldn't solve (b) and (c)?


I couldn't solve this question.. :s-smilie:

This one too .. :frown:


I got 40 and 5/8 for the logarithm question.
Reply 7
Original post by Funnycatvideos
I got 40 and 5/8 for the logarithm question.


Yeah, I actually just solved it now!!
Thank you!! :biggrin:
Original post by Adorable98
Yeah, I actually just solved it now!!
Thank you!! :biggrin:


You're very welcome.
Reply 9
Original post by Zacken
(a) is the cosine curve shifted pi/3 to the right; there's not much I can do to explain it, you should know your trig graphs and your function transformations.

(b) is just cosy=0\cos y = 0 (which you should know how to solve) and then back-substitute y=xπ3y = x - \frac{\pi}{3} and solve for xx.

(c) is just cosy=12\cos y = \frac{1}{\sqrt{2}} (Which you should know how to solve, one of the solutions is y=π4y = \frac{\pi}{4}) and then back-sub and solve for xx.

Perhaps you need to work on your concepts more before moving on to past papers? :redface:


Yeaah you're right!! Thaaank you!!:smile:
Original post by Adorable98
Could someone please help me with the following questions..:smile:


So I did (a) but couldn't solve (b) and (c)?


I couldn't solve this question.. :s-smilie:

This one too .. :frown:


For the Geometric sequences:
a)You use ar^n-1 a=300 r=1.05 n=24 so: 300*(1.05)^23=921.46=922 phones
b)You use the summation formula. I substituted the values in and I got 13351
c) You have to use ar^n-1 again:
300*1.05^N-1>3000
1.05^N-1>10
Take logs:
(N-1)log1.05>log10
N-1>log10/log1.05
N-1>47.19....
N>48.19...
N>48
(edited 7 years ago)
Original post by Funnycatvideos
For the Geometric sequences:
a)You use ar^n-1 a=300 r=1.05 n=24 so: 300*(1.05)^23=921.46=922 phones
b)You use the summation formula. I substituted the values in and I got 13351
c) You have to use ar^n-1 again:
300*1.05^N-1>3000
1.05^N-1>10
Take logs:
(N-1)log1.05>log10
N-1>log10/log1.05
N-1>47.19....
N>48.19...
N>48


Thanks

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