C1 Maths AS aqa 2016 (unofficial mark scheme new)

that makes sense thanks a lot for clearing that up for me. So if I wrote, translation by vector (-1/2,41/4) as my answer. would I get two marks for that ?

I think 7a was finding the tangent of the curve at P and part b was finding the x-coordinate of Q but I'm not entirely sure

Can someone confirm that m= -5/3 for 1a?

wasnt that six thought seven a and b was a differentiation then also 2nd derivative to find out if there was a minimum point

That was 8 :P

wasnt that six thought seven a and b was a differentiation then also 2nd derivative to find out if there was a minimum point

Unoffical Mark scheme for C1 AQA 2016

It would help if you could link answers to questions as i cant remember them

Questions:

1) a)Asked to work out gradient of a tangent, m= - 5/3 [2]
b)Asked to find co-ordinates of B B( - 3,4) [3]
c)Asked to find K K= - 30 [2]

2) a) simplify (3√5)^2 = 45 [1]
b) i cant remember the question but the answer was 75 - 32√5 [4]

3) a) y=(x-7/2)^2 - 41/4
b) min value = -41/4 [1]
c) Translation of (1/2 , 41/4)

4) a) show that (x+3) was a factor of x^3 - 5x^2 -8x + 48, p(-3) = 0, (x+3) is a factor of p(x).
b) three linear factors of p(x) = (x+3)(x-4)(x-4)
c) find remainder when p(x) was divided by (x+2) R=20
d) Factorise p(x) using (x+2) R = (x-2)(x^2-3x-14) + 20 [3]

5) a) asked to find equation of circle (x-5)^2+(y+3)^2=65 (note 65 = r^2) [3]
b) asked to find co-ordinates of B (AB is diameter) B ( 12, -7) [2]
c) asked to find equation of tangent at A 7x-4y+18=0 [5]
d) asked to find length of CT = 9 [2]

6) a) y=-32x-40
b)Q(-5/4) [1]
c) upside down positive graph passing through y axis at 8 [2]
d) x = -1±√5

7) a)
b)
c) definite integral = = 81 /4 [5]
d) area of shaded region = = 45/4 [3]


8) a) d^2y/dx^2= - 2x - 9x^2 [2]
b) verify that P was a minimum point sub x co-ordinate of P into dy/dx (given in the question) to prove it was a stationary point, then sub in x-coord of p into d^2y/dx^2 to get +45, d^2y/dx^2>0 therefore minimum point [4]
c) show that y is decreasing, so make your dy/dx<0 and rearrange to get into the form they wanted (note when you multiply by -1 the inequality sign flips)
d) cant remember anything except the answers were k>6 and k<-3/2

Answers that need a question to be assigned to
- k=4 and k=20

MARK SCHEME UPDATE:

Mark scheme is attached. Some answers are missing - please comment below if you know them!

Can someone confirm that m= -5/3 for 1a?

8) a) d^2y/dx^2= - 2x - 9x^2 [2]

b) verify that P was a minimum point sub x co-ordinate of P into dy/dx (given in the question) to prove it was a stationary point, then sub in x-coord of p into d^2y/dx^2 to get +45, d^2y/dx^2>0 therefore minimum point [4]

c)show that y is decreasing, so make your dy/dx<0 and rearrange to get into the form they wanted (note when you multiply by -1 the inequality sign flips)

d) cant remember anything except the answers were k>6 and k<-3/2 "

I believe these are correct?

Does anyone think the grade boundaries might be the lowest they've ever been this year? I've done every single past paper and This was just vile. There's an old paper (2013?) where it was like 56 for an A or something and that was way easier than this.

8) a) d^2y/dx^2= - 2x - 9x^2 [2]

b) verify that P was a minimum point sub x co-ordinate of P into dy/dx (given in the question) to prove it was a stationary point, then sub in x-coord of p into d^2y/dx^2 to get +45, d^2y/dx^2>0 therefore minimum point [4]

c)show that y is decreasing, so make your dy/dx<0 and rearrange to get into the form they wanted (note when you multiply by -1 the inequality sign flips)

d) cant remember anything except the answers were k>6 and k<-3/2 "

I believe these are correct?