Edexcel Core 3 - 21st June 2016 AM

Does anybody remember how many marks the sketching arcsin graph was?

Damm it this question cost me marks, no idea how i did but i got gradient as 10 (think i did 6+4) instead of (6-4) ff,so got the normal as -1/10 but i got y=16 and the method correct, any idea how many marks id lose?

How did you actually do the solve part of the arcsin graph where it was like 3f(x+1)+pi or whatever?

Partial fractions a was 3 b was 4


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am i the only one that didn't use partial fractions?

Arcsin(x+1)=pi/3
X+1=root3/2
X=root3/2-1

am i the only one that didn't use partial fractions?

Q1a, x=6, x=-5
b. a=6
2a. dy/dx = (20-4x^2)/(x^2+5)^2
b. x>rt(5) x<-rt(5)
3a. rt(5)cos(theta +26.57)
b. theta = 33.0, 273.9
c. theta = 86.1
4a. y=21, x=ln(2.5)
y=25 (k=25)
b. Proof
c. x1= 1.4368
x2= 1.4373
d. Show the change in sign. (gradient function)
5i. Turning points: 0.9463
ii. 0.5cosec(4y)
6a. A=3 B=4
b. x+2y-35=0 (or equivalent)
7a. arcsin(x) graph
b. x= -(2+rt(3))/2
8a. Proof
b. x= 0.294, -1.277, 1.865 and 1 more I think
9a. 6.740
b. Proof
c. T = 5ln(2+(2/e))

How did people do q1😭

Nah I used algebraic long division

Arcsin(x+1)=pi/3
X+1=root3/2
X=root3/2-1

what was Q 1a?