Edexcel Core 3 - 21st June 2016 AM

if G(x)= arcsin(x) then G(x+1)= arcsin(x) +1 not arcsin(x+1) so 3g(x+1) +pi = 3arcsin(x) +3 +pi

then continue to solve

if G(x)= arcsin(x) then G(x+1)= arcsin(x) +1 not arcsin(x+1) so 3g(x+1) +pi = 3arcsin(x) +3 +pi

then continue to solve

everything was correct expect my retard brain that say it was 2x-4/(x-2)^2 and decided to plus for some reason

Q1a, x=6, x=-5
b. a=6
2a. dy/dx = (20-4x^2)/(x^2+5)^2
b. x>rt(5) x<-rt(5)
3a. rt(5)cos(theta +26.57)
b. theta = 33.0, 273.9
c. theta = 86.1
4a. y=21, x=ln(2.5)
y=25 (k=25)
b. Proof
c. x1= 1.4368
x2= 1.4373
d. Show the change in sign. (gradient function)
5i. Turning points: 0.9463
ii. 0.5cosec(4y)
6a. A=3 B=4
b. x+2y-35=0 (or equivalent)
7a. arcsin(x) graph
b. x= -(2+rt(3))/2
8a. Proof
b. x= 0.294, -1.277, 1.865 and 1 more I think
9a. 6.740
b. Proof
c. T = 5ln(2+(2/e))

A bit higher usually

Few questions:

5ai - how many marks would one get for getting the turning point at 0.1608 rather than 0.9643,

6b how many marks would i get for finding the equation of normal for the simplified equation. I differentiated y= x^2 + 3 + (4x+12)/(x-2) and did the normal steps, I know the divison was wrong as forgot (x+3) on denominater. (Since part B was solely dependent on part A surely there would be marks for method)

8b I thought it was within the range -pi/2 and +pi/2 so only had 2 solutions within the limits, how many marks would i get/lose for this?

thanks

if G(x)= arcsin(x) then G(x+1)= arcsin(x) +1 not arcsin(x+1) so 3g(x+1) +pi = 3arcsin(x) +3 +pi

then continue to solve

How many marks for:

1) The inequality question (answers of sqrt5 and -sqrt5)
2) The question where you had to choose two values and show the change in sign
3) The question where you had to find the minimum value (answer of 80-something)

Would appreciate it if someone could tell me how many marks each of these were worth

Tough paper in comparison to others, I predict 64 for an a*

UMS estimates for 67/68?

no chance of 64 for an a*, its never been that low