For the buffer region in this, why does it stop the pH from increasing?
At the start:
CH3COOH + NaOH > CH3COONa + H2O
Which means there will be a high amount of salt in the solution, but why is this stopping the pH from rising? I thought it would actually make it rise further as the disassociated salt it reacts with water to form OH-?
What's reacting with the OH- in solution, that isn't there anyway? Seeing as, with a buffer solution, the acid is needed (CH3COOH + OH- > CH3COO- + H2O).
The acid concentration hasn't been increased?
Or is the presence of the dissasocated salt:
CH3COONa(aq) > CH3COO- + Na+
Causing the acid to reform:
CH3COO- + H2O > CH3COOH + OH-
<<< but there's more OH-!!Surely the Na+ isn't going to react with the OH-, as it will dissociate in the water.