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core 3 maths

Hi, i'm stuck on some trigonometry questions...
solve for x:
a) 3sin2xsecx=5 for 0<x<90
b)9cosx-12sinx=5 for 0<x<360
For (a), use sin2x=2sinxcosx\sin 2x=2 \sin x \cos x.

For (b), rewrite the LHS as Rcos(xa)R \cos (x-a)
Original post by BobbJo
For (a), use sin2x=2sinxcosx\sin 2x=2 \sin x \cos x.

For (b), rewrite the LHS as Rcos(xa)R \cos (x-a)


thank you so much!

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