AS level chemistry question
The equation for the hydrogenation of ethyne is C2H2 + 2H2 --> C2H6.
The experimental yield is 65%.
What is the mass I'm grads of ethane that can be produced from 16.20g of hydrogen.
The answer is 79.98g, please explain thanks
The experimental yield is 65%.
What is the mass I'm grads of ethane that can be produced from 16.20g of hydrogen.
The answer is 79.98g, please explain thanks
find number of moles of hydrogen
from equation deduce number of moles of ethane
hence find theoretical mass of ethane
hence from % yield, find actual mass of ethane
from equation deduce number of moles of ethane
hence find theoretical mass of ethane
hence from % yield, find actual mass of ethane
Original post by sahil kumar
The equation for the hydrogenation of ethyne is C2H2 + 2H2 --> C2H6.
The experimental yield is 65%.
What is the mass I'm grads of ethane that can be produced from 16.20g of hydrogen.
The answer is 79.98g, please explain thanks
The experimental yield is 65%.
What is the mass I'm grads of ethane that can be produced from 16.20g of hydrogen.
The answer is 79.98g, please explain thanks
Original post by BobbJo
find number of moles of hydrogen
from equation deduce number of moles of ethane
hence find theoretical mass of ethane
hence from % yield, find actual mass of ethane
from equation deduce number of moles of ethane
hence find theoretical mass of ethane
hence from % yield, find actual mass of ethane
Hi i did all of those steps still turned out to be wrong
number of moles of hydrogen = 8.1
number of moles of ethane =4.05
theoretical mass = 121.5
%yield = should be 78. 98 but im getting 7654.5 for sone reason lmao
Original post by sahil kumar
Hi i did all of those steps still turned out to be wrong
number of moles of hydrogen = 8.1
number of moles of ethane =4.05
theoretical mass = 121.5
%yield = should be 78. 98 but im getting 7654.5 for sone reason lmao
number of moles of hydrogen = 8.1
number of moles of ethane =4.05
theoretical mass = 121.5
%yield = should be 78. 98 but im getting 7654.5 for sone reason lmao
not sure what you are putting in the calculator to get that
Actual Mass / Theoretical mass = Percentage yield
so Actual mass = Percentage yield x Theoretical mass = 65/100 x 121.5 which does give 78.98g
Original post by BobbJo
not sure what you are putting in the calculator to get that
Actual Mass / Theoretical mass = Percentage yield
so Actual mass = Percentage yield x Theoretical mass = 65/100 x 121.5 which does give 78.98g
Actual Mass / Theoretical mass = Percentage yield
so Actual mass = Percentage yield x Theoretical mass = 65/100 x 121.5 which does give 78.98g
Thanks man got it i forgot to divide the 65/100
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