Completing the Square

GCSE Maths CGP The Student Book P137, Ex 1, Q3, H
Rewrite the quadratics below in the form (x +p)^2 =+ q

X^2 - 9x - 25

(x+p)^2 + q , p=b/2=(-9/2)
(x -9/2)(x - 9/2) = x^2 - 9x/2 - 9x/2 + 181/4
= x^2 - 9x + 181/4 (181/4 = 42.25)

so I need to get from +181/4 to (-25)
Therefore, 181/4 + (-25) = -281/4 = q
(x - 9/2)^2 - 281/4

However book answer is : (x - 9/2)^2 - 181/4
Is like they've ignored the -25

I see what you've tried to do

Please edit - it's against forum rules to post a solution

My bad I didn't know I'll rewrite it.

An example of another question would be: write x^2 +4x -6 in the form (x+p)^2 +q. To do this you would half the number with the x (4) and move the indice (^2)from the x to the outside of a bracket. After you do this you need to minus the square of the number you halved. This would look like (x+2)^2 -4 , and the -6 is still there so u put it back making it (x+2)^2-4 -6 which simplifies to (x+2)^2 -10 which would be your final answer.
In your question it is slightly more confusing as the number with the x is a 9 and half of that is 9/2 and thus you have fractions but either way you do the same as you do here.

Expand it out and compare to the original ... but 9 x 9 is not 181 btw