[br]$f(x) = x^3 + 2x^2 - x - 2 = 0$//[br]As $f(1) = 1 + 2 - 1 - 2 = 0$ then[br]$1$ is a root of $f(x)$ so that when $f(x)$ is divided by $(x-1)$ the remainder is 0.[br]
[br]$\frac{-b \pm \sqrt{b^2 -4ac}}{2a}$[br]
[br]$f(x) = x^3 + 2x^2 - x - 2 = 0$//[br]As $f(1) = 1 + 2 - 1 - 2 = 0$ then[br]$1$ is a root of $f(x)$ so that when $f(x)$ is divided by $(x-1)$ the remainder is 0.[br]
[br]$\frac{-b \pm \sqrt{b^2 -4ac}}{2a}$[br]
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