The Student Room Group
Reply 1
You should post this in the maths forum :smile:

For the first part, you should rearrange the original equation so you have x in terms of y, differentiate it with respect to y and then use the fact that dydx=1/(dxdy)\frac{dy}{dx} = 1/(\frac{dx}{dy}).

I'll have a look at the second part, I think you're going to have to use some nifty chain-ruling.
Reply 2
cheers I'm still working on it but think i've gotthe first part ok, and am working at the second part

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