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Again another stupid projectile

18) A particle is projected from a point with position vector (3i+3j)m relative to a fixed origin O where i and j are unit vectors in the horizontal and upward vertical directions respectively. Two seconds later the particles passes through the point with position vector (13i+8j)m. Find its initial velocity vector.
Reply 1
Deep456
18) A particle is projected from a point with position vector (3i+3j)m relative to a fixed origin O where i and j are unit vectors in the horizontal and upward vertical directions respectively. Two seconds later the particles passes through the point with position vector (13i+8j)m. Find its initial velocity vector.

Vertically:
s=5
a=-9.8
t=2
u=?

Horizontally:
s=10
a=0
t=2
u=?

Use an equation to work out the initial speed horizontally and the initial speed vertically.
Reply 2
starofale
Vertically:
s=5
a=-9.8
t=2
u=?

Horizontally:
s=10
a=0
t=2
u=?

Use an equation to work out the initial speed horizontally and the initial speed vertically.


s=ut+1/2at^2

Resolving vertically:
5=2u-19.6
24.6=2u
12.3=u

Resolving horizontalyl:
10=2u
u=5
Reply 3
Deep456
s=ut+1/2at^2

Resolving vertically:
5=2u-19.6
24.6=2u
12.3=u

Resolving horizontalyl:
10=2u
u=5

Yes, so its velocity vector would be 5i + 12.3j

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