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    • Thread Starter

    A tetrahedron V has vertices (0,0,0), (1,0,0), (0,1,0) and (0,0,1). Find the centre of volume, given by \frac{1}{V} \int_V \mathbf{x} dV
    I'm fairly sure I know how to do this, but I just need to clear a few things up.

    Firstly, dividing by V? A solid object? Is this just meant to mean the volume of V, or is this something that'll become clear in later lectures?

    Also, what is x? It's written as a vector, so do put it into x,y,z as (x+y+z) or is it just x?

    Thanks, and sorry for probably silly questions
    • Wiki Support Team

    Wiki Support Team
    You're right that it's terrible notation. You should divide by the volume of V. And x = (x,y,z) (where dV is shorthand for dx dy dz - yet more terrible notation, because they've already called the tetrahedron V). Vector calculus, eh...
    • Thread Starter

    Done. Thank you
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Updated: January 25, 2010
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