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Reply 40
For 4) I got, a=0.37 and b=4.5. :smile:
And when y=15, X was about 28, so x was 5.3.
the trig one was
cos(5x-20)=cos40
5x-20=+-40 + 360n
5x=20 +-40 +360n
x=4+-8+72n

the complex number was 5+10i (checked it with calculator)
step by step was 3.706
for the roots equation i got 5x^2-24x+72=0 (anyone get same, this one took a lot of work)
Reply 42
Cool stuff, got exactly the same :wink:

I think I slightly messed up the step by step question, but probably got a couple of marks. Nice exam, got around 90%
Reply 44
RYANDENNY
From memory, I got:

1. 3.706

2. 5 + 10i

3. 12° + n72° and 68° + n72°

4. a = 0.36, b = 4.8

5. It was a fairly obvious show that question

6a. 45° anticlockwise rotation
b. A reflection in the line y = tan(22.5)x
c. 90° anticlockwise rotation
d. Identity matrix, therefore no effect.
e. Reflection in the line y = x

7. 2 < x < 3, or x > 7/2

8. The points of intersection were (6, 2) and (6, -2)


That's just from memory though, might have gotten some of the question numbers wrong!


This sucks, I wrote rotation 360 degrees :frown:

I lost 4 marks in total, so that's 71. Not bad.....
Reply 45
I'm absolutely gutted! For question one I did newton rapheson at first, they didn't realize that it was Euler until 2 minutes to go, so I forgot to leave my answer in 3 sig figs...
Then for question 2 with the roots, I wrote &#945;+&#946;=4, and &#945;&#946;=10, but In 2c) I used &#945;+&#946;=10 & &#945;&#946;=4, that coupled with forgetting to simplify my answer is -2 marks also...
Hopefully I'll still get 72 though, but it was such an easy paper that I doubt UMS conversion'll do me any favours!

For the trig question I got:
72n +/- 8 + 4
(6 marks for that was beyond ridiculous!)

And I agree with most of you on the others, but was wondering how they wanted us to describe the identity matrix (as a reflection & re-reflection perhaps) it was worth two marks after all.
rob...

Then for question 2 with the roots, I wrote &#945;+&#946;=4, and &#945;&#946;=10, but In 2c) I used &#945;+&#946;=10 & &#945;&#946;=4, that coupled with forgetting to simplify my answer ,

whats wrong with &#945;+&#946;=10 & &#945;&#946;=4 that's what i got
but was wondering how they wanted us to describe the identity matrix (as a reflection & re-reflection perhaps) it was worth two marks after all.

i did some other past papers and there was a question like this, one mark was for saying it was the identity(does nothing) and the other saying B^2=I
Reply 47
Seems like I got majority of the trig one right - just messed up at the last bit, may have lost 2 or 3 marks there.
And i mixed up 6c and 6e and last part of qu 7. Got about 65-69/75 depending on how they mark the methods.
Overall - looking at a high B/Low A, but with so many people finding the paper easy I wonder how high they will make the grade boundaries!
Reply 48
Lol, I saved my main answers into the memory of my graphic so I could compare it with you guys.
I got:
1) 3.706
2) 5+10i
3) 72n+4±8
4) a=0.37, b=4.5
5) Pretty self-explanatory
6)a) Anticlockwise rotation about origin of 45°
b) Reflection in y=(tan22.5)x
c) Anticlockwise rotation about origin of 90°
d) No Effect (Anticlockwise rotation about origin of 0°)
e) Reflection in y=x
7) 2<x<3 and x>3.5
8) 5x^2 - 24x +72
9) Intersects at (6,2) and (6,-2)

I hope I was right cos I found it a fairly easy exam!
Reply 49
For question 4, wouldn't a=0.38? I got a = 3/8 or 0.375, and to 2d.p. that's 0.38... Or should I have been getting nowhere near 3/8?
Reply 50
Zuzuzu
For question 4, wouldn't a=0.38? I got a = 3/8 or 0.375, and to 2d.p. that's 0.38... Or should I have been getting nowhere near 3/8?


Well aa was the gradient right, so I used the lowest and highest values from the table that we plotted.

dydx=28.26644=22.260=0.37\dfrac{dy}{dx} = \dfrac{28.2 - 6}{64 - 4} = \dfrac{22.2}{60} = 0.37

And if you do a proper regression on your graphical calculator, it gives:

a = 0.37005813
b = 4.57325581
Totally messed up the Euler's step-by-step question, but I guess method and putting it to 3dp got me at least 2 marks.

The identity matrix question was nice. All I put was Identity matrix, therefore no transformation. I think that's the two points they want?
Reply 52
Also the last time a general solution trig question came up like that was in Jan06. :smile:

Find the general solution, in degrees, for the equation

sin(4x+10°)=sin50°sin(4x+10°) = sin50°


The mark scheme:

One solution is x = 10° B1 PI by general formula
Use of sin 130º = sin 50º M1 OE
Second solution is x = 30° A1 OE
Introduction of 90nº, or 360nº or 180nº M1 Or πn2\frac{\pi n}{2} or 2πn2\pi n or πn\pi n
GS (10 + 90n)°,(30 + 90n)° A1 5 OE; ft one numerical error or omission of 2nd soln
Reply 53
chronicl3
This sucks, I wrote rotation 360 degrees :frown:

I lost 4 marks in total, so that's 71. Not bad.....


Ahh unlucky! It's still practically the same thing though, so you could get the marks?

Even if you don't, 71 out of 75 in FP1 is definitely something to be proud of :')
Reply 54
hey_its_nay
the trig one was
cos(5x-20)=cos40
5x-20=+-40 + 360n
5x=20 +-40 +360n
x=4+-8+72n

the complex number was 5+10i (checked it with calculator)
step by step was 3.706
for the roots equation i got 5x^2-24x+72=0 (anyone get same, this one took a lot of work)


I did :smile:
Think I managed everything, really hoping I didn't have any 2+2=5 moments as the grade boundaries will probably be pretty high
Reply 56
I lost 5 makrs in total, which is probably like 90 UMS with it being so easy...
This pathetic excuse for an exam really did get the better of me :frown:
Reply 57
Damn... I screwed up majorly in the general solution question. Also, I got totally freaked out at the 'no effect' matrix...

And in the end I discovered my parabola was wrong...

In PC2 I reckon I have got at least 90%. But Stats this morning didn't go great. My mind drew a few blanks, and I ended up sitting there looking in wonder. Now I think back to the questions, and they were actually quite easy...

Still, I would be happy with a C in FP1... I guess...
It was an abomination of a paper, surely they shouldn't be allowed to make it that easy!!!
rob...
I lost 5 makrs in total, which is probably like 90 UMS with it being so easy...
This pathetic excuse for an exam really did get the better of me :frown:


Same sort of story here...it was TOO easy. I'm sure I've lost marks because of crossing out the right answer after having so much time to think about it.
Reply 59
Are you all seriously moaning about the paper being too easy?
Surely this is a good thing....

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