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Question involving Natural Log and Summutations

Hello.

First of all, here is the question:

Find i=1nln(2i)\displaystyle\sum_{i=1}^n ln(2^i) (whereby n = 50) , giving the answer in the form a ln 2, whereby a is an element of Q.

Okay, so i've never seen a question of this type before.

I don't even know where to start!

I know the log laws (although, I'm not supposed to use change of base).

Can someone please hint me in the right direction?

Thanks,
crayzrocker
(edited 13 years ago)
Reply 1
ln(2^i) = i ln 2
Reply 2
i=1nln(2i)i=1niln(2)ln(2)i=1ni\displaystyle\sum^{n}_{i=1}ln(2^i)\equiv\sum^{n}_{i=1}iln(2)\equiv ln(2)\sum^{n}_{i=1}i

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