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# Logs C2 ( I think) watch

1. Basically,

- 0.2 ln (1.5) + (0.2) ln 3

I know you need to write as a fraction but then what?
2. What are you trying to do with it? Factorise the 0.2 and then use the logA - logB rule.
3. aln(b) - aln(c) = aln(b/c)
4. 0.2ln2. But if I was writing it was (1/5)ln2, would I do it any differently?
5. (Original post by Deep456)
0.2ln2. But if I was writing it was (1/5)ln2, would I do it any differently?
Doesn't matter.
6. (Original post by StephenP91)

Doesn't matter.

Sorry, I didn't mean to anger you. Just making sure.
7. (Original post by Deep456)
Sorry, I didn't mean to anger you. Just making sure.
Haha, you didn't. The angry face was an accident.

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Updated: April 11, 2011
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