Logs C2 ( I think)

Basically,

- 0.2 ln (1.5) + (0.2) ln 3

I know you need to write as a fraction but then what?

What are you trying to do with it? Factorise the 0.2 and then use the logA - logB rule.

aln(b) - aln(c) = aln(b/c)

0.2ln2. But if I was writing it was (1/5)ln2, would I do it any differently?

0.2ln2. But if I was writing it was (1/5)ln2, would I do it any differently?

Doesn't matter.

(edited 13 years ago)

Original post by StephenP91

Doesn't matter.

Sorry, I didn't mean to anger you. Just making sure.

Sorry, I didn't mean to anger you. Just making sure.

Haha, you didn't. The angry face was an accident.

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