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OCR M1 - 31st May 2012 :)

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Reply 580
for that A and B and distance question, I subtracted 1 instead of adding 1, do you think this'll lose 1 or 2 marks?

also do you think it'll be possible to get full ums for 70-71/72?
Original post by h2shin
for that A and B and distance question, I subtracted 1 instead of adding 1, do you think this'll lose 1 or 2 marks?

also do you think it'll be possible to get full ums for 70-71/72?


I think this will lose you 1 if you laid it out as distance by A and distance by B and then looked at them together, but 2 if you did something strange. Hmm.... I'd have to wait for the general consensus to come out but I'm going to say that 71/72 will be 100.. so maybe :smile:
Reply 582
Original post by Nathdragon5
I think this will lose you 1 if you laid it out as distance by A and distance by B and then looked at them together, but 2 if you did something strange. Hmm.... I'd have to wait for the general consensus to come out but I'm going to say that 71/72 will be 100.. so maybe :smile:


ah cool, I didn't really think much about that question, I just worked out the difference in the distance that A and B travelled, then (obviously wrongly) reasoned that since A has to cover 1m less, it's distance from B is 1m less?

I just need a high mark in this to balance out the atrocity that is D1..
Original post by h2shin
ah cool, I didn't really think much about that question, I just worked out the difference in the distance that A and B travelled, then (obviously wrongly) reasoned that since A has to cover 1m less, it's distance from B is 1m less?

I just need a high mark in this to balance out the atrocity that is D1..


I think you just equated the distance that A travelled and the distance that B travelled plus 1.... I really can't remember mate, but if you got the same answer as me, you should be okay :smile:
Reply 584
Do you get error carried forwards? Primarily for the last question. Just say you got 7ii) wrong... (I put 3.11 + t)
Reply 585
Original post by Nathdragon5
I think you just equated the distance that A travelled and the distance that B travelled plus 1.... I really can't remember mate, but if you got the same answer as me, you should be okay :smile:


nah i got 10.6 instead of 12.6, cause difference was 11.6 so I should have added 1 instead of taking 1...:angry:
Reply 586
Original post by PreciseUrination
Could someone please walkthrough question 4? I don't remember getting 6.02 :/

i)R= 28-14sin30=21
Newton II
14cos30-21mu=0
mu=cos30/3=(sqrt3)/3=0.577

ii) New R (cos of force being removed)= 28N
F=mu R
mu=0.577
F=0.577 x 28
Newton II
0.577 x 28 = 28/9.8 x a
Rearrange to find a
s= 3.2 u=u v=0 a= -(0.577 x 9.8)
u= sqrt(2 x 3.2 x [0.577 x 9.8]) = 6.015765...
(edited 11 years ago)
Original post by samjj8
Do you get error carried forwards? Primarily for the last question. Just say you got 7ii) wrong... (I put 3.11 + t)


I believe so, yes :smile:

Original post by h2shin
nah i got 10.6 instead of 12.6, cause difference was 11.6 so I should have added 1 instead of taking 1...:angry:


Ahh damn, unlucky, otherwise agreeing with my answers
Has anyone got a worked answer for question on finding the initial velocity of the block?
Reply 589
For Q1 ii), was force E 15N, i.e. same as resultant from previous question?
Original post by Squire95
New R (cos of force being removed)= 28N
F=mu R
mu=0.577
F=0.577 x 28
Newton II
0.577 x 28 = 28/9.8 x a
Rearrange to find a
s= 3.2 u=u v=0 a= -(0.577 x 9.8)
u= sqrt(2 x 3.2 x [0.577 x 9.8]) = 6.015765...



Wierd, I remember doing all that and yet I got something around 14. Anyone want to help me in trying to find my mistake? I guess I divided something I should have multiplied.....
Reply 591
61/72 that's the minimum I reckon I got and the maximum is 66/72, any idea what type of UMS I am looking at?
Original post by Ivo
For Q1 ii), was force E 15N, i.e. same as resultant from previous question?


Yes it is the same as the resultant, but the resultant is 17N, not 15N.
Original post by Squire95
New R (cos of force being removed)= 28N
F=mu R
mu=0.577
F=0.577 x 28
Newton II
0.577 x 28 = 28/9.8 x a
Rearrange to find a
s= 3.2 u=u v=0 a= -(0.577 x 9.8)
u= sqrt(2 x 3.2 x [0.577 x 9.8]) = 6.015765...


I think my answer was 0.601 lol so I think I've divided by 98.8 instead of 9.8, not sure.. But I also did this a different way.
Original post by seamen
61/72 that's the minimum I reckon I got and the maximum is 66/72, any idea what type of UMS I am looking at?


I'm hoping 60 is around 85ums lol
Reply 595
Original post by tahseen1995
Yes it is the same as the resultant, but the resultant is 17N, not 15N.


OK, as long as it's the same as the resultant and angle is 180- the angle in i). Can you remember the two component forces, maybe I got 17 but can't remember.
Reply 596
Looks like 50/72. I'm fuming. Pressure on the C4 exam now!
Original post by Ivo
OK, as long as it's the same as the resultant and angle is 180- the angle in i). Can you remember the two component forces, maybe I got 17 but can't remember.


Yes, correct. The two components were 15 and 8.
Reply 598
Original post by As_Dust_Dances_
I'm hoping 60 is around 85ums lol


56 in January was an A and 48 is a B so 64 for 90 UMS?, and I found that extremely easy. Since there were 3 tricky questions in this exam, I reckon you need a bit lower than 64 maybe if your lucky 52 might be an A and 60 might be for 90 UMS.

I found this harder than any other past papers before so definetly lower than 56 for an A.
(edited 11 years ago)
Reply 599
How many marks would I get out of 6 for part 2 of Question 4 for this:
I used the correct method i.e v^2= u^2 + 2as but I made an error at the start as I didn't subtract the 14cos30 from R to get the new friction. So I ended with 5.27 (i can't remember exactly) rather than 6.02

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