Q. 1 (c) (iii) Predict the proton NMR spectrum for methanol by completing the table below.
I'm just unsure as to why the splitting of both types of proton is 'none'? Surely one would be a doublet and the other a quartet, or have I got the n+1 rule mixed up?
Q. 1 (c) (iii) Predict the proton NMR spectrum for methanol by completing the table below.
I'm just unsure as to why the splitting of both types of proton is 'none'? Surely one would be a doublet and the other a quartet, or have I got the n+1 rule mixed up?
OH protons do not couple, otherwise you would be right.
OH protons do not couple, otherwise you would be right.
Ah I see, looking back on my notes that is correct But why would that cause both peaks to be single? Sorry just a little confused with this topic, thanks though!
Ah I see, looking back on my notes that is correct But why would that cause both peaks to be single? Sorry just a little confused with this topic, thanks though!
As the methyl group is unable to couple to the OH, so the methyl group is a singlet and the OH group is a singlet.