The Student Room Group

D1 - Simplex algorithm question

Question paper :

www.ocr.org.uk/Images/57757-question-paper-unit-4736-decision-mathematics-1.pdf

Mark scheme :

http://www.ocr.org.uk/Images/61150-mark-scheme-january.pdf

Question 6) part iii

I understand how you work out the values of p and x from the table but how does you get the values of y and z as what they are ???

Also the last part iv)

I don't understand it can someone please explain it?
Reply 1
Original post by IShouldBeRevising_
Question paper :

www.ocr.org.uk/Images/57757-question-paper-unit-4736-decision-mathematics-1.pdf

Mark scheme :

http://www.ocr.org.uk/Images/61150-mark-scheme-january.pdf

Question 6) part iii

I understand how you work out the values of p and x from the table but how does you get the values of y and z as what they are ???

Also the last part iv)

I don't understand it can someone please explain it?


For part (iii) y and z aren't assigned to any particular row so they both equal zero. Remember the algorithm works by increasing the decision variables in turn to find the optimal value of P, similar to vertex testing, so this means by default all decision variables start as 0.

Part (iv) can be explained as the most (and only) negative value in row P consists of all negative entries. This means the problem cannot be solved as we cannot proceed to compare pivot entries as they will all be below 0 (which the algorithm is supposed to ignore).

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