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GCSE Maths - Area of a Segment - Help?

Hello there, long time since I've done Maths at any level, and I'm having some problems getting my head around this question.



I've dug out some old books... and found out that...

(x = angle in degrees)

Area of circle = Pi x r squared

Area of sector = (x/360) x Area of full circle

Area of segment = Area of sector - area of triangle

So I think I found out the area of the sector ok as it came to Pi.

Area of circle = Pi * 2 squared = 4Pi

Then... area of sector = (90/360) * 4 Pi

Which equals Pi.

But now I'm completely thrown by the area of the segment...

Can anyone advise on the next step(s)?

Thank you.
Reply 1
Original post by Massey1337
Hello there, long time since I've done Maths at any level, and I'm having some problems getting my head around this question.



I've dug out some old books... and found out that...

(x = angle in degrees)

Area of circle = Pi x r squared

Area of sector = (x/360) x Area of full circle

Area of segment = Area of sector - area of triangle

So I think I found out the area of the sector ok as it came to Pi.

Area of circle = Pi * 2 squared = 4Pi

Then... area of sector = (90/360) * 4 Pi

Which equals Pi.

But now I'm completely thrown by the area of the segment...

Can anyone advise on the next step(s)?

Thank you.



Since you know x you can use the rule that a triangle has area 12absinC\frac{1}{2} ab \sin C where C is the angle between sides a and b

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