You know that at the point of intersection, that both the x and y values must be the same. So y = y - can you see where to go from here (it's the same process as finding the intersection between a straight line y = mx + c and a quadratic y = ax^2 + bx + c)?
You know that at the point of intersection, that both the x and y values must be the same. So y = y - can you see where to go from here (it's the same process as finding the intersection between a straight line y = mx + c and a quadratic y = ax^2 + bx + c)?
thanks for trying to help but I've labelled the graphs wrong. the n and m should swap over. And I don't really understand what you mean.
Well, another way to d this is to say that at the point of intersection, both lines much have the same co-ordinates (otherwise they aren't intersecting). And so you can say that:
y1 = y2
Where y1 is the y value of the first equation and y2 the equation of the second one. And so replace each y with the other half of its equation:
2x = x + 6 x = 6
As you found. Subbing x = 6 into y = 2x then gives the full co=ordinates of the point of intersection (6,12).
So, using this method, can you see how you could find the points of intersection for your curves?
Well, another way to d this is to say that at the point of intersection, both lines much have the same co-ordinates (otherwise they aren't intersecting). And so you can say that:
y1 = y2
Where y1 is the y value of the first equation and y2 the equation of the second one. And so replace each y with the other half of its equation:
2x = x + 6 x = 6
As you found. Subbing x = 6 into y = 2x then gives the full co=ordinates of the point of intersection (6,12).
So, using this method, can you see how you could find the points of intersection for your curves?
Yh, but the questions I have x as a power. Am not really good with powers