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    how to finds coordinates when two exponential graphs insect?

    help with this please
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    You know that at the point of intersection, that both the x and y values must be the same. So y = y - can you see where to go from here (it's the same process as finding the intersection between a straight line y = mx + c and a quadratic y = ax^2 + bx + c)?
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    (Original post by tory88)
    You know that at the point of intersection, that both the x and y values must be the same. So y = y - can you see where to go from here (it's the same process as finding the intersection between a straight line y = mx + c and a quadratic y = ax^2 + bx + c)?
    thanks for trying to help but I've labelled the graphs wrong. the n and m should swap over. And I don't really understand what you mean.
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    (Original post by Purple27)
    thanks for trying to help but I've labelled the graphs wrong. the n and m should swap over. And I don't really understand what you mean.
    Would you know how to find the point of intersection of two straight lines?
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    (Original post by tory88)
    Would you know how to find the point of intersection of two straight lines?
    yh you can find out using simultaneous equations
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    (Original post by Purple27)
    yh you can find out using simultaneous equations
    So if I had two lines:

    (1) y = 2x
    (2) y = x + 6

    How would you find their point of intersection?
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    (Original post by tory88)
    So if I had two lines:

    (1) y = 2x
    (2) y = x + 6

    How would you find their point of intersection?
    by moving the x to the other side


    x= 6 y=12
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    (Original post by Purple27)
    by moving the x to the other side


    x= 6 y=12
    Well, another way to d this is to say that at the point of intersection, both lines much have the same co-ordinates (otherwise they aren't intersecting). And so you can say that:

    y1 = y2

    Where y1 is the y value of the first equation and y2 the equation of the second one. And so replace each y with the other half of its equation:

    2x = x + 6
    x = 6

    As you found. Subbing x = 6 into y = 2x then gives the full co=ordinates of the point of intersection (6,12).

    So, using this method, can you see how you could find the points of intersection for your curves?
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    (Original post by tory88)
    Well, another way to d this is to say that at the point of intersection, both lines much have the same co-ordinates (otherwise they aren't intersecting). And so you can say that:

    y1 = y2

    Where y1 is the y value of the first equation and y2 the equation of the second one. And so replace each y with the other half of its equation:

    2x = x + 6
    x = 6

    As you found. Subbing x = 6 into y = 2x then gives the full co=ordinates of the point of intersection (6,12).

    So, using this method, can you see how you could find the points of intersection for your curves?
    Yh, but the questions I have x as a power. Am not really good with powers
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    (Original post by Purple27)
    Yh, but the questions I have x as a power. Am not really good with powers
    OK, so go as far as you can and post where you get stuck.
 
 
 
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