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Statistics: the mean

This is from jan 2006 s1 ocr: 2iii) calculate the mean height of all 150 plants.
We are given the information, 50 plants has mean of 124.5cm, 100 plants has a mean of 123.0cm.
I don't understand what the mark scheme is saying: (124.5+123*2)/3.
Please help!!!
Reply 1
Original post by Christina Tiana
This is from jan 2006 s1 ocr: 2iii) calculate the mean height of all 150 plants.
We are given the information, 50 plants has mean of 124.5cm, 100 plants has a mean of 123.0cm.
I don't understand what the mark scheme is saying: (124.5+123*2)/3.
Please help!!!

50 plants have a mean of 124.5 which means that when you divide the total weight of the 50 plants by 50 you get 124.5. So the total weight of the 50 plants must be 124.5 x 50.

Do the same thing for the 100 plants then add the two total weights together and divide by the total number of plants (150).
Reply 2
Original post by Christina Tiana
This is from jan 2006 s1 ocr: 2iii) calculate the mean height of all 150 plants.
We are given the information, 50 plants has mean of 124.5cm, 100 plants has a mean of 123.0cm.
I don't understand what the mark scheme is saying: (124.5+123*2)/3.
Please help!!!


I'm not sure about the markscheme, but here's what my solution would be:

Mean = total/n. If the mean for 50 plants is 124.5 cm, then the total height of all those plants is 50x124.5 = 6225cm. The same for the 100 plants, 100x123 = 12300cm. Add these together, 6225 + 12300 = 18525. This is the total height of all 150 plants, so the mean height of all 150 plants is 18525/150 = 123.5cm
Reply 3
Original post by Lau14
I'm not sure about the markscheme, but here's what my solution would be:

Mean = total/n. If the mean for 50 plants is 124.5 cm, then the total height of all those plants is 50x124.5 = 6225cm. The same for the 100 plants, 100x123 = 12300cm. Add these together, 6225 + 12300 = 18525. This is the total height of all 150 plants, so the mean height of all 150 plants is 18525/150 = 123.5cm

Please don't post full solutions - it's against the rules of this forum.
Thank you! That method is on the mark scheme too, I understand it but I want to understand the method the mark scheme is saying, as the method you guys are suggesting is only in the 'acceptable' box. But thank you anyway!
Reply 5
Original post by Christina Tiana
Thank you! That method is on the mark scheme too, I understand it but I want to understand the method the mark scheme is saying, as the method you guys are suggesting is only in the 'acceptable' box. But thank you anyway!


The markscheme is just taking a shortcut by cancelling the factor of 50 in the numerator and demominator.

The numerator contains (something x 50 which leaves something x 1 when you cancel a 50) + (something else x 100 which leaves something else x 2 when you cancel a 50)

The denominator is 150 in total which is just 50 x 3

So all they've done is just cancel the 50s.

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