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Edexcel C2 20th May 2015 Official Thread

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Reply 860

username1162972

Original post by ToLiveInADream

Guys, should I do the rest of the Solomon papers I haven't done or do the R/IAL c2 papers? Which is harder?

Do the R/IAL

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Reply 861

WhiteyBread101

Original post by tw15st3d

if we have a CAST question in radians, is it alright to give answers as decimals instead of in terms of pi? i know it isn't necessarily as accurate but do you still get the marks?

It's fine to do it in decimals, often the answer won't be able to be written easily in terms of pi. If the answer is a precise part of pi though, then write it in terms of pi :yes:

Reply 862

pearl_rose

Original post by FluffyCherry

These are the shapes that we should know.

Thank you, however I can't open that post for some reason... can you email it to me if I PM you my email?

Reply 863

FluffyCherry

Original post by pearl_rose

Thank you, however I can't open that post for some reason... can you email it to me if I PM you my email?

Okay

Reply 864

Tplox

Original post by Ahsen2015

you done all the other past papers?

pretty much
im just going through the gold c2 past papers and the international papers really
looking at last year international, seems like they are making c2 harder :s

Reply 865

ToLiveInADream

Original post by physicsmaths

Do the R/IAL

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Cool. I'll just finish off the solomon I'm doing atm ^.^

Reply 866

Olon

Does anyone know how you find chord length?

(edited 8 years ago)

Reply 867

ToLiveInADream

Original post by Olon

Does anyone know how you find chord length?

Depends. Usually you construct a right-angled triangle and do Pythagoras from there.

Reply 868

joe1545

Original post by physicsmaths

Do the R/IAL

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Solomon papers are harder, but if you haven't done the R papers do them

Reply 869

frozo123

Original post by Olon

Does anyone know how you find chord length?

Get the two coordinates of the chord
use this
d^2= (x2-x1)^2 + (y2-y1)^2
where d is the length

Reply 870

Olon

Original post by ToLiveInADream

Depends. Usually you construct a right-angled triangle and do Pythagoras from there.

can you give me an example please?

Reply 871

Olon

Original post by frozo123

Get the two coordinates of the chord
use this
d^2= (x2-x1)^2 + (y2-y1)^2
where d is the length

so can i use this everytime? instead of constructing a right angle and using pythagoras?
is it square rooted btw?

(edited 8 years ago)

Reply 872

ToLiveInADream

Original post by Olon

can you give me an example please?

Yeah, sure. There's loads of odd questions they do them in. Try: https://a44694f152ee562e38a9454969d2b9a549a03543.googledrive.com/host/0B1ZiqBksUHNYOTR1Zk42aXdIazg/09%20Gold%201%20-%20C2%20Edexcel.pdf question 9c.

Draw a CLEAR and labelled diagram or it may get confusing.

Reply 873

ToLiveInADream

Original post by frozo123

Get the two coordinates of the chord
use this
d^2= (x2-x1)^2 + (y2-y1)^2
where d is the length

What about if you don't have the coordinate points? Eg. the question I gave the other poster above.

Reply 874

username1162972

Original post by joe1545

Solomon papers are harder, but if you haven't done the R papers do them

Yes but realistically if you get a really hard question then it will be ones very similar to the R papers. Since its the day before much better to do the R IAL papers. IAL can get particularly nasty.

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Reply 875

Olon

Original post by ToLiveInADream

Ah, thanks. Is this essentially the same as using the formula the other poster wrote?

Reply 876

n2697

Guys how do you work out B? Can you explain it step by step? Thanks

Reply 877

Jbrown1997

Original post by Olon

Does anyone know how you find chord length?

If you have the co-ordinates of the points where it touches the triangle, just use Pythagoras to find the length of the chord.

Reply 878

frozo123

Original post by ToLiveInADream

What about if you don't have the coordinate points? Eg. the question I gave the other poster above.

are you trying to test me or are you stuck on it lol

Reply 879

ToLiveInADream

Original post by Olon

Ah, thanks. Is this essentially the same as using the formula the other poster wrote?

I suppose you potentially could do it that way, but it would be extremely long (pages of working out + time) to get the coordinates in the first place. You would have to use parallel gradient, work out the line, work out where they intersect the triangle etc etc..

Using pythagoras makes more sense to me, but if you really can't see where the triangle to construct would be, do it.

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